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Law Incorporation [45]
3 years ago
11

The following graph shows the distance Thomas is from his home (in meters) for a period of 2 minutes. Determine the average rate

of change for the first 50 seconds, explain what this means in context of the problem. Then find the average rate of change for the 70 remaining seconds

Mathematics
1 answer:
irga5000 [103]3 years ago
6 0
The answer:
<span>the average rate of change for the first 50 seconds:
it  is v= 100 m/ 50 s = 2 m/s
</span><span>Thomas speed is 2 m in each second for the first 50 seconds.

</span><span>The average rate of change for the 70 remaining seconds:
the time is between [70; 120]
so the distance is d= 200m - 40m= 160m
the average rate is
v= 160m / 70 s = 2 . 28m /s

</span>
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Find the roots of the function f(x) = 3x4 - 48.
Andrew [12]

Answer:

x=\pm 2\text{ or } x = \pm 2i

Step-by-step explanation:

We are given:

0=3x^4-48

Factor:

0=3(x^4-16)

Difference of Two Squares:

0=3(x^2-4)(x^2+4)

Zero Product Property:

(x^2-4)=0\text{ or } x^2+4=0

Solve:

x^2=4\text{ or } x^2=-4

Take the square root. Since we are taking an even-root, it requires plus/minus:

x=\pm 2\text{ or } x = \pm 2i

6 0
3 years ago
1. Joe works as a hair stylist. He
love history [14]
If you’re looking for expressions for those,

1. 20x + 30

2. 45x
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3 years ago
Question #45 plz all answers will help
Veseljchak [2.6K]
To solve this, you can use this equation:

1530 ÷ 15 = x

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6 0
3 years ago
Your monthly living expenses are $1500 on an income of $1,650 per month. Your goal is to have an emergency fund of 4 times your
Aneli [31]
For the answer to the question above, your end goal is to have $6,000 total in 12 months. since you have $2400 already you can subtract that from 6,000 leaving you with $3600 over the course of 12 months. since you already put $150 in a month over the course of 12 months you would have $1800 which is only half of the goal of $3600. in order for you to put in $3600, you would have to put an additional 150 in your savings along with your regular 150 making Letter B the answer.
4 0
3 years ago
Read 2 more answers
I have corner points of:
WARRIOR [948]
The points you found are the vertices of the feasible region. I agree with the first three points you got. However, the last point should be (25/11, 35/11). This point is at the of the intersection of the two lines 8x-y = 15 and 3x+y = 10

So the four vertex points are:
(1,9)
(1,7)
(3,9)
(25/11, 35/11)

Plug each of those points, one at a time, into the objective function z = 7x+2y. The goal is to find the largest value of z

------------------

Plug in (x,y) = (1,9)
z = 7x+2y
z = 7(1)+2(9)
z = 7+18
z = 25
We'll use this value later. 
So let's call it A. Let A = 25

Plug in (x,y) = (1,7)
z = 7x+2y
z = 7(1)+2(7)
z = 7+14
z = 21
Call this value B = 21 so we can refer to it later

Plug in (x,y) = (3,9)
z = 7x+2y
z = 7(3)+2(9)
z = 21+18
z = 39
Let C = 39 so we can use it later

Finally, plug in (x,y) = (25/11, 35/11)
z = 7x+2y
z = 7(25/11)+2(35/11)
z = 175/11 + 70/11
z = 245/11
z = 22.2727 which is approximate
Let D = 22.2727

------------------

In summary, we found
A = 25
B = 21
C = 39
D = 22.2727

The value C = 39 is the largest of the four results. This value corresponded to (x,y) = (3,9)

Therefore the max value of z is z = 39 and it happens when (x,y) = (3,9)

------------------

Final Answer: 39

7 0
3 years ago
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