Answer:
you want 4 correct and 16 incorrect
there are 20 questions
each question has four answers, so
P(right answer) = 1/4
P(wrong answer) = 3/4
----
Since you want 4 correct of 20 we have a combination of 20C4
This is a binomial problem where p = 1/4, q = 3/4 and we get
(20 "choose" 4)*(probability correct)^(number correct)*(probability incorrect)^(number incorrect)
putting numbers in we get
(20c4)*(1/4)^4*(3/4)^16
This gives us
~ .189685
Step-by-step explanation:
Answer:
23
Step-by-step explanation:
225/25 = 21
21+2=23
9.014 , 9.789 , 9.991
Good luck
3x+y=9 ....(1)
3x-5y=15. ......(2)
-[3x-5y=15]
=> 3x+ y = 9
-3x+5y=-15
..........................
0 +6y=-6
so,y=-1
3x+(-1)=9
3x=10
x=10/3
Answer:
quadratic monomial, quadratic trinomial, constant monomial, linear monomial, quadratic binomial, linear binomial.
Step-by-step explanation:
two quadratic trinomials each have a degree-2, degree-1, and degree-0 term. It is possible that the coefficients of all or some of the terms cancel each other while adding or subtracting the polynomials.
