The sample space of the experiment (i.e. the total number of ways he can pick 7 random pages out of a total of 6 + 4 = 10 pages) is given by:
If he picks at least 5 pages of maths homework, this means that he either picked 5 pages or 6 pages of maths homework.
The number of ways he can pick 5 or 6 maths homework is given by:
Therefore, the probability that he recovers at least 5 pages of his math homework is given by:
S + 2.8 = 6.59
s = ?
To solve for s use the inverse operation of addition, which is subtraction.
s + 2.8 = 6.59
6.59 - 2.8 = s
6.59 - 2.8 = 3.79
s = 3.79
Check:
s + 2.8 = 6.59
s = 3.79
3.79 + 2.8 = ?
3.79 + 2.8 = 6.59
Correct!
This proves: s = 3.79 ;)
Answer:
Quesiton is not clear. here is the asnswer basing on our understand
Step-by-step explanation:
(8-32)3 = (-24*3) = =72
Answer:
13<y+x<32
Step-by-step explanation:
It depends.
If x and y are Whole Numbers, it would be 14<y+x<31.
If x and y are Real Numbers, including decimals and fractions, it would be 13<y+x<32
Since it doesn’t specify, it’s probably the latter.
Answer:
Step-by-step explanation:
Number of vertices
3
Variable constraints
a>0 and b>0
Diagonal lengths
(data not available)
Height
b
Area
A = (a b)/2
Centroid
x^_ = (a/3, b/3)
Mechanical properties:
Area moment of inertia about the x-axis
J_x invisible comma x = (a b^3)/12
Area moment of inertia about the y-axis
J_y invisible comma y = (a^3 b)/12
Polar moment of inertia
J_zz = 1/12 a b (a^2 + b^2)
Product moment of inertia
J_x invisible comma y = -1/24 a^2 b^2
Radii of gyration about coordinate axes
r_x = b/sqrt(6)
r_y = a/sqrt(6)
Distance properties:
Side lengths
a | sqrt(a^2 + b^2) | b
Hypotenuse
sqrt(a^2 + b^2)
Perimeter
p = sqrt(a^2 + b^2) + a + b
Inradius
r = 1/2 (-sqrt(a^2 + b^2) + a + b)
Circumradius
R = 1/2 sqrt(a^2 + b^2)
Generalized diameter
sqrt(a^2 + b^2)
Convexity coefficient
χ = 1
Mean triangle area
A^_ = (a b)/24
