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2 years ago

Find the area of the following: -square whose sides are (x+1) in length

Mathematics

2 answers:

KiRa [710]2 years ago

6 0

Answer:

Area of the square = $x^2+2x+1$

Step-by-step explanation:

We need to find the area of the square

The side length of the square is (x+1)

Area of the square formula is (side)^2

Replace side with x+1

So the area of the square = $(x+1)^2$

$(x+1)^2= (x+1)(x+1)= x^2+x+x+1= x^2+2x+1$

Area of the square = $x^2+2x+1$

Rainbow [258]2 years ago

4 0

Area of Square = Base*Height
Base=(x+1) Height=(x+1)
Therefore Area=(x+1)(x+1) or (x+1)^2
By expanding the brackets e.g. x*x is x^2 then x*1 is x and so on you get:
x^2+x+x+1 this simplfies to x^2+2x+1
Area = x^2=2x+1
Unless they have given you a value for x, this is the equation for the area of said square.

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