At sea level atmospheric pressure is 1 bar absolute (1 standard atmosphere =101 kPa=1.013 bars). The weight of the atmosphere exerts a pressure which will support a column of water 10 m high; 10 m under water the pressure on a diver is 200 kPa. The volume of gas in an early diving bell full of air at sea level is halved at 10 m according to Boyle’s law; at 20 m pressure is 300 kPa absolute and the gas is compressed into one third the volume.
Dry air is composed of roughly 21% oxygen, 78% nitrogen, and 1% other gases. According to Dalton’s law the partial pressure of oxygen at any depth will be 21% of the total pressure exerted by the air and the partial pressure of nitrogen will be 78% of total pressure.
Gases dissolve in the liquid with which they are in contact. Nitrogen is fat soluble and at sea level we have several litres dissolved in our bodies. If the partial pressure of nitrogen is doubled (by breathing air at 10 m depth) for long enough for equilibration to take place we will contain twice as many dissolved nitrogen molecules as at sea level.
Answer:
20
Step-by-step explanation:
For the sake of the problem, let's make female workers "x" and male workers "y".
x+y<40 This equation shows that the total number of workers has a max of 40.
30x+20y<1,000 This equation shows that the total cost the manager pays ($30 to each woman, $20 to each man) has a max of $1,000.
Now you can solve for x and y.
X+y<40
-y -y
X<-y+40
Substitute -y+40 in for X in the second equation
30(-y+40)+20y<1,000
-30y+1200+20y<1,000 Distribute
-10y+1,200<1,000 Combine like terms
-10y<-200 Subtract 1,200
y>20 Divide by -10; flip the sign
Since y>20, and y=male workers, you now know that the minimum
number of male workers he should send is 20
You can set up an system of equations
x=2y+8
x-y=25
Substitute x in to the second equation
2y+8-y=25
y+8=25
y=17
Substitute the y back in to the first equation.
x=2(17)+8=42
Answer:
the total are is 459
Step-by-step explanation:
3 3/16 divided by 1/8 = 25 1/2 or 25.5
2 1/4 divided by 1/8 = 18
so 18 x 25.5 = 459
hope this helps
Answer:
Step-by-step explanation:
Let the function of quantity in the lung of air be A(t)
So 
so, A(t) = Amax sin t + b
A(t) = 2.8t⇒ max
A(t) = 0.6t ⇒ min
max value of A(t) occur when sin(t) = 1
and min value of A(t) = 0
So b = 0.6
and A(max) = 2.2
at t = 2 sec volume of a is 0.6
So function reduce to
and t = 5 max value of volume is represent
so,
when t = 5
so the equation becomes
