Answer:
Step-by-step explanation:
b

now, if we a "prime factoring" of each number, we get
204 =
2*2*3*17
120 = 2*
2*2*3*5
168 = 2*
2*2*3*7
now, notice the GCD for all three is that common bolded values, namely 2*2*3, or 12, so each room will house 12 participants,
now, how many rooms for all German? 204 ÷ 12, or 17 rooms.
how many rooms for all English ones? 120 ÷ 12, or 10 rooms.
how many rooms for the French ones? 168 ÷ 12, or 14 rooms.
so the total amount of rooms for all of them is
17 + 10 + 14.
The set is linearly dependent.
To explicitly prove this, we need to show there is at least one choice of constants
such that

or equivalently,

which is the same as solving the system of equations

From the first and last equations, we have
and
. Substituting these into the second equation leaves us with
, and so the overall solution set is

for which there are infinitely many not-all-zero solutions.
Answer:
It's probably B
Step-by-step explanation:
Answer:
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