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Pavel [41]
3 years ago
14

What is 300 mi converted into km?

Mathematics
1 answer:
skad [1K]3 years ago
5 0

Answer: 482.8032 km.

Step-by-step explanation: ...

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Can someone please help me!!!
pochemuha

Answer:

Step-by-step explanation:

b

5 0
3 years ago
In a seminar, the number of participants in German, English and French are 204, 120 and 168 respectively. Find the numbers of ro
postnew [5]
\bf \stackrel{German}{204}\qquad \stackrel{English}{120}\qquad \stackrel{French}{168}

now, if we a "prime factoring" of each number, we get

204 = 2*2*3*17

120 = 2*2*2*3*5

168 = 2*2*2*3*7

now, notice the GCD for all three is that common bolded values, namely 2*2*3, or 12, so each room will house 12 participants,

now, how many rooms for all German?  204 ÷ 12, or 17 rooms.

how many rooms for all English ones?  120 ÷ 12, or 10 rooms.

how many rooms for the French ones?  168 ÷ 12, or 14 rooms.

so the total amount of rooms for all of them is 17 + 10 + 14.
3 0
3 years ago
MATRECIES: Suppose ={u,v,w}⊆R3 is linearly independent. Determine if the set 4 ={u, v, v−w, u+v+w} is linearly independent or li
AlladinOne [14]

The set is linearly dependent.

To explicitly prove this, we need to show there is at least one choice of constants c_1,c_2,c_3,c_3\in\Bbb R such that

c_1 u + c_2 v + c_3(v-w) + c_4(u+v+w) = 0

or equivalently,

(c_1 + c_4) u + (c_2 + c_3 + c_4) v + (-c_3 + c_4) w = 0

which is the same as solving the system of equations

\begin{cases} c_1 + c_4 = 0 \\ c_2 + c_3 + c_4 = 0 \\ -c_3 + c_4 = 0 \end{cases}

From the first and last equations, we have c_1=-c_4 and c_3=c_4. Substituting these into the second equation leaves us with c_2-2c_1=0, and so the overall solution set is

c_1 = \dfrac12 c_2 = -c_3 = -c_4

for which there are infinitely many not-all-zero solutions.

3 0
2 years ago
Some studies show that high school students are more successful when the school day begins after 9 am. To test this theory,
Alex Ar [27]

Answer:

It's probably B

Step-by-step explanation:

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3 years ago
Identify the number of moles of each element present in one mole of NH NO3.
Sergio039 [100]

Answer:

no se jejfjekqkznbeoqnzne

7 0
3 years ago
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