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sesenic [268]
3 years ago
5

Hellojdbshsvejdjduxyxbdbecenrlxndbdhdnfbbfbd​

Mathematics
2 answers:
shutvik [7]3 years ago
4 0
What’s up? What u need
babunello [35]3 years ago
4 0

Answer:

amnds hfbwoufnqokejrdfhcuhf

Step-by-step explanation:

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A set of stickers contains 4 hearts for every 6 stars. Which choice contains an equivalent ratio of hearts to start?
Yuri [45]

Answer:

6 hearts to 9 stars

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Write an inequality to match the problem.<br> There are at least 28 days in every month.
Elodia [21]

Answer:

28 ≥ month

Step-by-step explanation:

5 0
3 years ago
If it takes 4 men 6hours to repair a road, how long will it take 7 men to do the job if they work at the same rate.
Crank
Tricky question. This isn't a ratio question even though it seems like one.

First divide 7 by 4.
7 \div 4 = 1.75

With more men, the hours taken to repair a road will be even shorter.

So next divide 6 by 1.75.
6 \div 1.75 = 3.43

Answer : It'll take 3.43 hours to do the job if they work at the same rate.

Hope this helps. - M
4 0
3 years ago
Graph ∆KLM with vertices K(2,2), L(0,- 1), and M(-3,2). Graph ∆K'L'M' with a scale factor of 2. What are the coordinates of the
olasank [31]

Answer:

The coordinates of the new vertices are:

K'(4,4), L'(0,- 2), and M'(-6,4).

Step-by-step explanation:

In order to dilate a shape by 2, you can simply multiply the coordinates of the orignal triangle each by 2 to find the new coordinates of the new vertices.

K(2,2), L(0,- 1), and M(-3,2)

K'(2*2,2*2), L'(0*2,- 1*2), and M'(-3*2,2*2).

Now become...

K'(4,4), L'(0,- 2), and M'(-6,4).

You can now graph ∆K'L'M' using these coordinates.

5 0
2 years ago
Subtract (x^2+3x-4) -(4x-2x^2-3)
Feliz [49]

Answer:

3 x^2 - x + -1

Step-by-step explanation:

Simplify the following:

-(4 x - 2 x^2 - 3) + x^2 + 3 x - 4

Factor -1 out of -2 x^2 + 4 x - 3:

--(2 x^2 - 4 x + 3) + x^2 + 3 x - 4

(-1)^2 = 1:

2 x^2 - 4 x + 3 + x^2 + 3 x - 4

Grouping like terms, 2 x^2 + x^2 + 3 x - 4 x - 4 + 3 = (x^2 + 2 x^2) + (3 x - 4 x) + (-4 + 3):

(x^2 + 2 x^2) + (3 x - 4 x) + (-4 + 3)

x^2 + 2 x^2 = 3 x^2:

3 x^2 + (3 x - 4 x) + (-4 + 3)

3 x - 4 x = -x:

3 x^2 + -x + (-4 + 3)

3 - 4 = -1:

Answer: 3 x^2 - x + -1

4 0
3 years ago
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