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scoundrel [369]

3 years ago

15

Some doctors recommend that no more than 30% of a person's daily calories come from fats. Following this recommendation, if you

eat 2,400 calories In a day, what is the maximum number of calories that should come from fats?

1 answer:

White raven [17]3 years ago

8 0

2400 divided by 10 is 240 and 240 x 3 = 720 so your answer would be 720 calories per day

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qaws [65]

NUMBER ONE IS THE RIGHT ANGLE AND THE SECIND INE IS SUPPLEMENTARY

8 0

2 years ago

Which equation shows the point slope form of the line the glasses through (3,2) and has a slope of 1/3

7nadin3 [17]

B

The equation of a line in ' point- slope form ' is

y - b = m( x - a )

where m is the slope and (a, b ) a point on the line

here m = $\frac{1}{3}$ and (a, b ) = (3, 2 )

y - 2 = $\frac{1}{3}$ ( x - 3 ) → in point- slope form

6 0

3 years ago

Read 2 more answers

2/5 +3/10= simplest form

NNADVOKAT [17]

Add those together is 7/10

3 0

3 years ago

Read 2 more answers

1.) Find the length of the arc of the graph x^4 = y^6 from x = 1 to x = 8.

xxTIMURxx [149]

First, rewrite the equation so that <em>y</em> is a function of <em>x</em> :

$x^4 = y^6 \implies \left(x^4\right)^{1/6} = \left(y^6\right)^{1/6} \implies x^{4/6} = y^{6/6} \implies y = x^{2/3}$

(If you were to plot the actual curve, you would have both $y=x^{2/3}$ and $y=-x^{2/3}$ , but one curve is a reflection of the other, so the arc length for 1 ≤ <em>x</em> ≤ 8 would be the same on both curves. It doesn't matter which "half-curve" you choose to work with.)

The arc length is then given by the definite integral,

$\displaystyle \int_1^8 \sqrt{1 + \left(\frac{\mathrm dy}{\mathrm dx}\right)^2}\,\mathrm dx$

We have

$y = x^{2/3} \implies \dfrac{\mathrm dy}{\mathrm dx} = \dfrac23x^{-1/3} \implies \left(\dfrac{\mathrm dy}{\mathrm dx}\right)^2 = \dfrac49x^{-2/3}$

Then in the integral,

$\displaystyle \int_1^8 \sqrt{1 + \frac49x^{-2/3}}\,\mathrm dx = \int_1^8 \sqrt{\frac49x^{-2/3}}\sqrt{\frac94x^{2/3}+1}\,\mathrm dx = \int_1^8 \frac23x^{-1/3} \sqrt{\frac94x^{2/3}+1}\,\mathrm dx$

Substitute

$u = \dfrac94x^{2/3}+1 \text{ and } \mathrm du = \dfrac{18}{12}x^{-1/3}\,\mathrm dx = \dfrac32x^{-1/3}\,\mathrm dx$

This transforms the integral to

$\displaystyle \frac49 \int_{13/4}^{10} \sqrt{u}\,\mathrm du$

and computing it is trivial:

$\displaystyle \frac49 \int_{13/4}^{10} u^{1/2} \,\mathrm du = \frac49\cdot\frac23 u^{3/2}\bigg|_{13/4}^{10} = \frac8{27} \left(10^{3/2} - \left(\frac{13}4\right)^{3/2}\right)$

We can simplify this further to

$\displaystyle \frac8{27} \left(10\sqrt{10} - \frac{13\sqrt{13}}8\right) = \boxed{\frac{80\sqrt{10}-13\sqrt{13}}{27}}$

7 0

3 years ago

Rationalize the numerator

julsineya [31]

Answer:

It is about 1.2

Hope it helps

4 0

3 years ago