What are two pair fractions with common denominators for 3/5 and 3/4

1 answer:

6 0

The cheap answer is, you simply "grab the denominator of one and multiply it times the other's top and bottom", so let's do so,

$\bf \cfrac{3}{5}\cdot \cfrac{4}{4}\implies \cfrac{12}{20}\qquad \qquad \qquad \qquad \qquad \cfrac{3}{4}\cdot \cfrac{5}{5}\implies \cfrac{15}{20}$

You might be interested in

I need the answer to this fast<br> Please

jeyben [28]

The initial function is slope

=> slope = 7-1/6-0 = 6/6 = 1

Hope this helps you :)

5 0

2 years ago

Find the coordinates of the point D (6, - 3) after the transformation (x,y)

yKpoI14uk [10]

For X, you add three which gives you
6+3=9

And for Y, you subtract 2:
-3-2=-5

Your coordinates are (9,-5)

7 0

2 years ago

What are the solutions to the quadratic equation -2x^2 + 6x + 3 = 0?

mario62 [17]

For this, we will be using the quadratic formula, which is $x=\frac{-b+/-\sqrt{b^2-4ac}}{2a}$ , with a=x^2 coefficient, b=x coefficient, and c = constant. Our equation will look like this: $x=\frac{-6+/-\sqrt{6^2-4*(-2)*3}}{2*(-2)}$

Firstly, solve the multiplications and the exponents: $x=\frac{-6+/-\sqrt{36+24}}{-4}$

Next, do the addition: $x=\frac{-6+/-\sqrt{60}}{-4}$

Next, your equation will be split into two: $x=\frac{-6+\sqrt{60}}{-4},\frac{-6-\sqrt{60}}{-4}$ . Solve them separately, and your answer will be $x=-0.436,3.436$