Answer:
Step-by-step explanation:
We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean
For the null hypothesis,
µ = 25235
For the alternative hypothesis,
µ > 25235
This is a right tailed test.
Since the population standard deviation is not given, the distribution is a student's t.
Since n = 100,
Degrees of freedom, df = n - 1 = 100 - 1 = 99
t = (x - µ)/(s/√n)
Where
x = sample mean = 27524
µ = population mean = 25235
s = samples standard deviation = 6000
t = (27524 - 25235)/(6000/√100) = 3.815
We would determine the p value using the t test calculator. It becomes
p = 0.000119
Since alpha, 0.05 > than the p value, 0.000119, then we would reject the null hypothesis. There is sufficient evidence to support the claim that student-loan debt is higher than $25,235 in her area.
3/4 of the garden is not potatoes, or 75%
The sum is 10s^2t-5st^2. With two separate sections it’s a binomial, and the sum of the powers of the variables is 2+1=3, it has a degree of 3.
60/500=?/100
60/5=12
12/100
12%.
Answer:
She has 16 friends
Step-by-step explanation:
40 minus 8 is 32 so that divided by 2 is 16
