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3 years ago

What’s 14 divided by 16 in this problem

Mathematics

1 answer:

Bas_tet [7]3 years ago

3 0

You can just simplify the fraction 14/16 by dividing both the numerator and denominator by 2, which will leave you with the answer of 7/8.

If you really need 14/16 in decimal form (which I don't think you will, most equations allow you to have a fraction as an answer), then 14/16 = 0.875.

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If 5x - 2 = -12, then x =

Drupady [299]

Answer:

x=-2

Step-by-step explanation:

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3 years ago

Read 2 more answers

Evaluate 3a + 5a2 when a = 2. Question 1 options: 26 44 484 106

sukhopar [10]

Plug in 2 wherever you see 'a'

3(2) + 5(2)(2)

1. 3×2 = 6, so:

6 + 5(2)(2)

2. 5×2=10, 10×2=20, so:

6 + 20

The final answer is 26.

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4 years ago

5a + 5b + 5c + 5d<br> Which expression is another way to write the expression shown here?

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4 years ago

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yawa3891 [41]

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3 years ago

6) Two coastguard stations P and Q are 17km apart, with due East of P. A ship S is observed in distress on a bearing 048° fromP

adelina 88 [10]

Answer:

The ship S is at 10.05 km to coastguard P, and 12.70 km to coastguard Q.

Step-by-step explanation:

Let the distance of the ship to coastguard P be represented by x, and its distance to coastguard Q be represented by y.

But,

<P = 048°

<Q = $360^{o}$ - $324^{o}$

= 0 $36^{o}$

Sum of angles in a triangle = $180^{o}$

<P + <Q + <S = $180^{o}$

048° + 0 $36^{o}$ + <S = $180^{o}$

$84^{o}$ + <S = $180^{o}$

<S = $180^{o}$ - $84^{o}$

= $96^{o}$

<S = $96^{o}$

Applying the Sine rule,

$\frac{y}{Sin P}$ = $\frac{x}{Sin Q}$ = $\frac{z}{Sin S}$

$\frac{y}{Sin P}$ = $\frac{z}{Sin S}$

$\frac{y}{Sin 48^{o} }$ = $\frac{17}{Sin 96^{o} }$

$\frac{y}{0.74314}$ = $\frac{17}{0.99452}$

⇒ y = $\frac{12.63338}{0.99452}$

= 12.703

y = 12.70 km

$\frac{x}{Sin Q}$ = $\frac{z}{Sin S}$

$\frac{x}{Sin 36^{o} }$ = $\frac{17}{Sin 96^{o} }$

$\frac{x}{0.58779}$ = $\frac{17}{0.99452}$

⇒ x = $\frac{9.992430}{0.99452}$

= 10.0475

x = 10.05 km

Thus,

the ship S is at a distance of 10.05 km to coastguard P, and 12.70 km to coastguard Q.

6 0

3 years ago