Answer: x = 9/4, y = 7/6
║<span>2x + 3y = 8
</span>║<span>4x - 6y = 2
</span>║4x + 6y = 16
║4x - 6y = 2
Add both equations together:
8x = 18
x = 9/4
Sub x = 9/4 into 2x + 3y = 8
2(9/4) + 3y = 8
9/2 + 3y = 8
3y = 7/2
y = 7/6
Answer:
.403645833 square inches
Step-by-step explanation:
1 5/8-1 equals 5/8
8.75-1 equals 7.75
7.75/12 equals .6458
.6458 times 5/8 equals .4 square inches
Answer:
- r(0) = <0, 100> . . . . . . . .meters
- r'(0) = <7.071, 7.071> . . . . meters per second
Step-by-step explanation:
<u>Initial Position</u>
The problem statement tells us we're measuring position from the ground at the base of the building where the projectile was launched. The initial horizontal position is presumed to be zero. The initial vertical position is said to be 100 meters from the ground, so (in meters) ...
r(0) = <0, 100>
<u>Initial Velocity</u>
The velocity vector resolves into components in the horizontal direction and the vertical direction. For angle α from the horizontal, the horizontal component of velocity is v₁·cos(α), and the vertical component is v₁·sin(α). For v₁ = 10 m/s and α = π/4, the initial velocity vector (in m/s) is ...
r'(0) = <10·cos(π/4), 10·sin(π/4)>
r'(0) ≈ <7.071, 7.071>
Answer:
(a + b + c)/2
Step-by-step explanation:
Number of kids in first class: a
Number of kids in second class: b
Number of kids in third class: c
The total number of kids in all classes is: a + b + c
The total number of kids is divided equally between 2 buses:
(a + b + c)/2
