True. For example, if 2 is a, and b was 0, then ab would automatically be 0. Both a and b can be 0 though, but at least one of them must be zero.
3(v + 2) + 4 = 13
Mutiply the bracket by 3
(3)(v)= 3v
(3)(2)= 6
3v+6+4= 13
3v+10=13
Move +10 to the other side
Sign changes from +10 to -10
3v+10-10= 13-10
3v= 13-10
3v= 3
divide both sides by 3
3v/3= 3/3
v= 1
Answer : v= 1
(-4)^2-4(1)(5)
16-4(1)(5)
16-4(5)
16-20
-4
The discriminant is negative so there are no real number solutions.
Answer:
<h2>The easiest to solve for is x in the first equation</h2>
Step-by-step explanation:
Given the system of equation, x + 4 y = 14. and 3 x + 2 y = 12, to solve for x, we can use the elimination method of solving simultaneous equation. We need to get y first.
x + 4 y = 14............ 1 * 3
3 x + 2 y = 12 ............ 2 * 1
Lets eliminate x first. Multiply equation 1 by 3 and subtract from equation 2.
3x + 12 y = 42.
3 x + 2 y = 12
Taking the diffrence;
12-2y =42 - 12
10y = 30
y = 3
From equation 1, x = 14-4y
x = 14-4(3)
x = 14-12
x = 2
It can be seen that the easiest way to get the value of x is by using the first equation and we are able to do the substitute easily <u>because the variable x has no coefficient in equation 1 compare to equation 2 </u>as such it will be easier to make the substitute for x in the first equation.
Answer:
She has 80 apples in all.
Step-by-step explanation:
24=30%
(24÷3)=(30÷3)%
8=10%
(8×10)=(10×10)%
80=100%
