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2 years ago

A man weighs k kg. He goes on a diet and

Mathematics

1 answer:

Natasha_Volkova [10]2 years ago

3 0

Answer:

His weight is 9/10 of what it used to be before.

Step-by-step explanation:

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Help please I’ll give Brainly please answer both I’ll give 5 stars and lines

Llana [10]

Answer:

I really cant see the picture that well or, i would help.

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Every weekday, Mr. Jones bikes from his home to his job. Sometimes he rides along two roads, the long route that is shown by the

notka56 [123]

Answer:

(A)6 kilometers

Step-by-step explanation:

First, we determine the value of a using Pythagoras Theorem.

$Hypotenuse^2=Opposite^2+Adjacent^2\\17^2=a^2+15^2\\a^2=17^2-15^2\\a^2=289-225\\a^2=64\\a^2=8^2\\a=8$ km$

Therefore:

Distance along the long route = 8 + 15 =23 km

Distance along the shortcut =17 km

Difference =23-17 =6km

Therefore, Mr. Jones bikes 6km less when he takes the shortcut instead of the long route.

5 0

2 years ago

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. Approximate each of the following logarithms to four decimal places. Use the LOG key on your calculator rather than logarithm

Free_Kalibri [48]

Answer:

$log_2(6)=2.584$

Step-by-step explanation:

Here the logarithm has base 2

$log_2(3^2)=log_2(6)$

Let

$log_2(6)=x$

$log_ya=x\\\Rightarrow y^x=a$

$\\\Rightarrow 2^x=6$

Now, take logarithm to the base 10

$log 2^x=log6\\\Rightarrow xlog2=log6\\\Rightarrow x=\frac{log6}{log2}\\\Rightarrow x=2.584$

So, $log_2(6)=2.584$

5 0

2 years ago

Solve this system of linear equations. Separate the x- and y- values with a comma.

liubo4ka [24]

Answer:

(-1,4)

Step-by-step explanation:

Using elimination, add the two equations to get rid of the y variable.

17x = 43 - 15y

+8x = -68 + 15y

=25x = -25

x = -1

Now plug in -1 for x in any of the equations.

17(-1) = 43 - 15y

-17 = 43 - 15y

-60 = -15y

y = 4

6 0

3 years ago

A sample of 1000 college students at NC State University were randomly selected for a survey. Among the survey participants, 102

cupoosta [38]

Answer:

The upper endpoint of the 99% confidence interval for population proportion is 0.13.

Step-by-step explanation:

The confidence interval for population proportion is:

$CI=\hat p\pm z_{\alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

Given:

n = 1000

$\hat p$ = 0.102

$z_{\alpha /2}=z_{0.01/2}=z_{0.005}=2.58$

*Use the standard normal table for the critical value.

Compute the 99% confidence interval for population proportion as follows:

$CI=\hat p\pm z_{\alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n}}\\=0.102\pm 2.58\times\sqrt{\frac{0.102(1-0.102)}{1000}}\\=0.102\pm0.0248\\=(0.0772, 0.1268)\\\approx (0.08, 0.13)$

Thus, the upper limit of the 99% confidence interval for population proportion is 0.13.

6 0

2 years ago