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motikmotik
3 years ago
15

Say you own 5,715 shares of Sanden Research Labs, each of which pays a yearly dividend of $14.66. How much do you receive in div

idends every year? a. $83,781.90 b. $81,729.50 c. $75,865.50 d. $93,954.60
Mathematics
1 answer:
Mrrafil [7]3 years ago
7 0

Answer:

A:83,781.90

Step-by-step explanation:

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For any number n>1, is
Simora [160]
The right answer is A ! :)
7 0
3 years ago
If j and k are nonzero integers, which pair of points must lie in the same quadrant?
Marizza181 [45]
<h3>Answer:  Choice D.   (3j, 3k)  and (3/j, 3/k)</h3>

The slash indicates a fraction.

=============================================

Proof:

We'll need to consider 4 different cases.

-----------------------

Case (1): j > 0 and k > 0

If j > 0, then 3j > 0 and 3/j > 0

If k > 0, then 3k > 0 and 3/k > 0

The two points (3j, 3k) and (3/j, 3/k) are both in quadrant 1.

-----------------------

Case (2): j > 0 and k < 0

If j > 0, then 3j > 0 and 3/j > 0

If k < 0, then 3k < 0 and 3/k < 0

Points (3j, 3k) and (3/j, 3/k) are both in quadrant 4.

------------------------

Case (3): j < 0 and k > 0

If j < 0, then 3j < 0 and 3/j < 0

If k > 0, then 3k > 0 and 3/k > 0

Points (3j, 3k) and (3/j, 3/k) are in quadrant 3.

------------------------

Case (4): j < 0 and k < 0

If j < 0, then 3j < 0 and 3/j < 0

If k < 0, then 3k < 0 and 3/k < 0

Points (3j, 3k) and (3/j, 3/k) are in quadrant 4.

------------------------

For nonzero integers j and k, we've shown that Points (3j, 3k) and (3/j, 3/k) are in the same quadrant. This concludes the proof.

8 0
2 years ago
Read 2 more answers
The average of p, q, and r is 40. The average of a, b, c, and d is 5. What is the average of a, b, c, d, p, q, and r?
Pachacha [2.7K]

Answer:

20

Step-by-step explanation:

Average = sum of numbers divided by number of numbers

sum of p q and r: 40*3=120

sum of a b c and d: 5*4=20

sum of a b c d p q r: 120+20=140

average of a b c d p q r: 140/7, or 20

3 0
3 years ago
(1 point) The distribution of heights of adult men in the U.S. is approximately normal with mean 69 inches and standarddeviation
Ludmilka [50]

Part a)

The mean height is 69 inches with a standard deviation of 2.5 inches.

If we consider a interval of heights that relies on no more than two standard deviations from the mean, we will cover, approximatelly, 95% of men's heights. Then, we interval that we're looking for is:

Answer: 64 TO 74 INCHES

Part b)

Since [69,74] is half of the interval in the previous answer, we might expect half of 95% as the percentage of men who are in this interval. That is:

Answer: 47.5 PERCENT

Part c)

A interval of heights that relies on no more than one standard deviation from the mean covers, approximatelly, 68% of men's heights. Then, we can consider that the percentage of men that are between 64 and 66.5 inches is given by 47.5 - 68/2 = 13.5.

Answr: 13.5 PERCENT

3 0
1 year ago
Sin 20° cos 40° cos 80° = 1​
mr Goodwill [35]

Answer:

I think that the answer is 1/8 NOT 1

Step-by-step explanation:

6 0
2 years ago
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