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2 years ago

Helpppppplpppo! Plz plz hurry

Mathematics

1 answer:

Nuetrik [128]2 years ago

8 0

Answer: it’s no solution inconsistent

Step-by-step explanation:

Multiply the top by -2

The x’s and y’all cancel out

0=-6

=0 which means no solution I think

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Complete the following diamond problems.

Phoenix [80]

Answer : Top cell = 12 ; Bottom cell = 7

Step-by-step explanation:

The rules of a diamond problem states that, one should add the two numbers (3 and 4) to get the value in the bottom cell and multiply the two numbers (3 and 4) again to get the value in the top cell.

Therefore; Top cell, 3×4= 12 Bottom cell, 3+4 = 7.

7 0

2 years ago

What is an equation of the line that passes through the point (−6,−1) and is perpendicular to the line 6x−y=7?

user100 [1]

Answer:

y=-1/6x-2

Step-by-step explanation:

Lets find the slope of the given line

6x-7=y,m=6

The slope of the perpendicular line would be=-1/6

Using the point-slope form y-y1=m(x-x1)

y--1=-1/6(x--6)

y+1=-1/6(x+6)

6y+6=-x-6

6y=-x-6-6

6y=-x-12

y=-1/6x-2

6 0

2 years ago

Let a and b be roots of x² - 4x + 2 = 0. find the value of a/b² +b/a²

erastovalidia [21]

Answer:

$\dfrac{a}{b^2}+\dfrac{b}{a^2}=10$

Step-by-step explanation:

Given equation: $x^2-4x+2=0$

The roots of the given quadratic equation are the values of x when $y=0$ .

To find the roots, use the quadratic formula:

$x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0$

Therefore:

$a=1, \quad b=-4, \quad c=2$

$\begin{aligned}\implies x & =\dfrac{-(-4) \pm \sqrt{(-4)^2-4(1)(2)}}{2(1)}\\& =\dfrac{4 \pm \sqrt{8}}{2}\\& =\dfrac{4 \pm 2\sqrt{2}}{2}\\& =2 \pm \sqrt{2}\end{aligned}$

$\textsf{Let }a=2+\sqrt{2}$

$\textsf{Let }b=2-\sqrt{2}$

Therefore:

$\begin{aligned}\implies \dfrac{a}{b^2}+\dfrac{b}{a^2} & = \dfrac{2+\sqrt{2}}{(2-\sqrt{2})^2}+\dfrac{2-\sqrt{2}}{(2+\sqrt{2})^2}\\\\& = \dfrac{2+\sqrt{2}}{6-4\sqrt{2}}+\dfrac{2-\sqrt{2}}{6+4\sqrt{2}}\\\\& = \dfrac{(2+\sqrt{2})(6+4\sqrt{2})+(2-\sqrt{2})(6-4\sqrt{2})}{(6-4\sqrt{2})(6+4\sqrt{2})}\\\\& = \dfrac{12+8\sqrt{2}+6\sqrt{2}+8+12-8\sqrt{2}-6\sqrt{2}+8}{36+24\sqrt{2}-24\sqrt{2}-32}\\\\& = \dfrac{40}{4}\\\\& = 10\end{aligned}$