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3 years ago

Helpppppplpppo! Plz plz hurry

Mathematics

1 answer:

Nuetrik [128]3 years ago

8 0

Answer: it’s no solution inconsistent

Step-by-step explanation:

Multiply the top by -2

The x’s and y’all cancel out

0=-6

=0 which means no solution I think

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For her exercise today, Keiko plans to both run and swim. Let r be the number of laps she runs and let s be the number of laps s

DerKrebs [107]

Answer:

5r + 3s ≥ 30

Step-by-step explanation:

We know Keiko wants to do exercise at least 30 minutes a day, and she wants ideally to mix up the activities, by combining running and swimming into her schedule.

Since each lap she runs takes 5 minutes and each lap she swims takes 3 minutes, these will be the left side of the inequality:

5r + 3s

She wants to exercise at least 30 minutes a day, so...

5r + 3s ≥ 30

she could do 3 laps of running and 5 laps of swimming for example.

6 0

3 years ago

I will give brainliest answer

earnstyle [38]

Answer:

A translation by 1 units to the right and 3 units down.

Step-by-step explanation:

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3 years ago

A group of learners is trying to identify the vertices of the feasible region from the graph shown below during a Live Classroom

wel

Answer:

what do you want us to answer?

Step-by-step explanation:

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3 years ago

Jasmine is buying beans. She bought r pounds of red beans that cost $2 per pound and b pounds of

horsena [70]

Answer:

A and B (2r and 7b)

Step-by-step explanation:

If she has black beans that cost $7 per pound the expression should be 7b. Hope this helps! Lmk if you have any more questions.

4 0

2 years ago

For what value of the constant c is the function fcontinuous on (−[infinity], [infinity])?

Arlecino [84]

Answer:

For $c=\frac{1}{7}$ the function f(x) is continuous on $(-\infty,\infty)$ .

Step-by-step explanation:

We have the following function

$f(x) = \left\{ \begin{array}{ll} cx^2+5x & \quad x$

For the function f(x) to be continuous on $(-\infty,\infty)$ it is sufficient to have continuity at x = 6, we need to ensure that as x approaches 6, the left and right limits match, this means that

$\lim_{x \to 6^{-} } f(x)=\lim_{x \to 6^{+} } f(x)=f(x)$ ,

which holds if and only if

$c\left(6\right)^2+5\left(6\right)=\left(6\right)^2-c\left(6\right)\\36c+30=36-6c\\42c=6$

namely if $c=\frac{1}{7}$ .

6 0

3 years ago