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Talja [164]
3 years ago
8

Helpppppplpppo! Plz plz hurry

Mathematics
1 answer:
Nuetrik [128]3 years ago
8 0

Answer: it’s no solution inconsistent

Step-by-step explanation:

Multiply the top by -2

The x’s and y’all cancel out

0=-6

=0 which means no solution I think

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For her exercise today, Keiko plans to both run and swim. Let r be the number of laps she runs and let s be the number of laps s
DerKrebs [107]

Answer:

5r + 3s ≥ 30

Step-by-step explanation:

We know Keiko wants to do exercise at least 30 minutes a day, and she wants ideally to mix up the activities, by combining running and swimming into her schedule.

Since each lap she runs takes 5 minutes and each lap she swims takes 3 minutes, these will be the left side of the inequality:

5r + 3s

She wants to exercise at least 30 minutes a day, so...

5r + 3s ≥ 30

she could do 3 laps of running and 5 laps of swimming for example.

6 0
3 years ago
I will give brainliest answer
earnstyle [38]

Answer:

A translation by 1 units to the right and 3 units down.

Step-by-step explanation:

7 0
3 years ago
A group of learners is trying to identify the vertices of the feasible region from the graph shown below during a Live Classroom
wel

Answer:

what do you want us to answer?

Step-by-step explanation:

3 0
3 years ago
Jasmine is buying beans. She bought r pounds of red beans that cost $2 per pound and b pounds of
horsena [70]

Answer:

A and B (2r and 7b)

Step-by-step explanation:

If she has black beans that cost $7 per pound the expression should be 7b. Hope this helps! Lmk if you have any more questions.

4 0
2 years ago
For what value of the constant c is the function fcontinuous on (−[infinity], [infinity])?
Arlecino [84]

Answer:

For c=\frac{1}{7} the function f(x) is continuous on (-\infty,\infty).

Step-by-step explanation:

We have the following function

f(x) = \left\{        \begin{array}{ll}            cx^2+5x & \quad x

For the function f(x) to be continuous on (-\infty,\infty) it is sufficient to have continuity at x = 6, we need to ensure that as x approaches 6, the left and right limits match, this means that

\lim_{x \to 6^{-} } f(x)=\lim_{x \to 6^{+} } f(x)=f(x),

which holds if and only if

c\left(6\right)^2+5\left(6\right)=\left(6\right)^2-c\left(6\right)\\36c+30=36-6c\\42c=6

namely if c=\frac{1}{7}.

6 0
2 years ago
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