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3 years ago

Harold collected data on the daily high temperature in two cities over a period of one week.

Mathematics

1 answer:

Misha Larkins [42]3 years ago

3 0

Answer:

Correct choices are 1 and 4

Step-by-step explanation:

As per data given we have:

Median temperature is 75°F and 88°F
And the range from the median is 5° for both cities

This gives us lowest temperatures of:

75° -5° = 70° and 88° - 5°= 83° respectively

And high temperatures are:

75° + 5° = 80° and 88° + 5° = 93°

Answer choices based on above details:

Choice 1 - correct
Choice 2 - incorrect. Correct answer is 93°
Choice 3 - incorrect. Correct answer is 93° - 70° = 23°
Choice 4 - correct

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Through:(3,-1),slope=-1

Wewaii [24]

Answer:

y = -x + 2

Step-by-step explanation:

Use the point-slope formula y - k = m(x -h):

y - [-1] = -1(x - 3), or

y + 1 = -x + 3, or

y = -x + 2

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3 years ago

Divided 2) Ellie made $253 for 22 hours of work. She makes $11 per hour so Identify the error:

patriot [66]

Answer:

Ellie should have made 253$ in 23 hours in time. If she worked for 22 hours, then she made 242$.

Step-by-step explanation:

253$ / 11$= 23 hours

22 hours X 11$= 242 hours

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3 years ago

In the pulley system shown in this figure, MQ = 30 mm, NP = 10 mm, and QP = 21 mm. Find MN.

ankoles [38]

<h2>Answer:</h2>

$\boxed{\overline{MN}=37.96}$

<h2>Step-by-step explanation:</h2>

For a better understanding of this problem, see the figure below. Our goal is to find $\overline{MN}$ . Since:

$\angle MRS=\angle MQP=90^{\circ} \\ \\ \overline{MQ}=\overline{MR}=30mm$

and $\overline{MN}$ is a common side both for ΔMRN and ΔMQN, then by SAS postulate, these two triangles are congruent and:

$\overline{RN}=\overline{QN}$

By Pythagorean theorem, for triangle NQP:

$\overline{QN}=\sqrt{\overline{NP}^2+\overline{QP}^2} \\ \\ \overline{QN}=\sqrt{10^2+21^2} \\ \\ \overline{QN}=\sqrt{541}$

Applying Pythagorean theorem again, but for triangle MQN:

$\overline{MN}=\sqrt{\overline{MQ}^2+\overline{QN}^2} \\ \\ \overline{MN}=\sqrt{30^2+(\sqrt{541})^2} \\ \\ \boxed{\overline{MN}=37.96}$

3 0

3 years ago

How do you get the perimeter of a triangle, all side are 28 cm?

Alisiya [41]

Perimeter of the triangle, a+b+c

In this case, a=b=c=28

So, perimeter would be 28*3 = 84 cm

7 0

3 years ago

At Clucker's Chicken, a bucket of 4 pieces of dark meat and 5 pieces of white meat costs 7.05. A bucket of 3 pieces of dark meat

Alenkinab [10]

Answer:

The cost of a piece of dark meat is $0.70 and the cost of a piece of white meat is $0.85.

Step-by-step explanation:

Given:

At Clucker's Chicken, a bucket of 4 pieces of dark meat and 5 pieces of white meat costs 7.05.

A bucket of 3 pieces of dark meat and 8 pieces of white meat costs 8.90.

Now, to find the cost of a piece of dark meat and the cost of a piece of white meat.

Let the cost of a piece of dark meat be $x.$

And the cost of a piece of white meat be $y.$

A bucket of 4 pieces of dark meat and 5 pieces of white meat costs $7.05.

So,

$4x+5y=7.05$

$4x=7.05-5y$

$x=\frac{7.05-5y}{4}$ .......(1)

Now, a bucket of 3 pieces of dark meat and 8 pieces of white meat costs $8.90.

$3x+8y=8.90$

Substituting the value of $x$ from equation (1) we get:

$3(\frac{7.05-5y}{4})+8y=8.90$

$\frac{21.15-15y}{4} +8y=8.90$

$\frac{21.15-15y+32y}{4} =8.90$

Multiplying both sides by 4 we get:

$21.15-15y+32y=35.60$

$21.15+17y=35.60$

Subtracting both sides by 21.15 we get:

$17y=14.45$

Dividing both sides by 17 we get:

$y=0.85$

The cost of a piece of white meat = $0.85.

Now, substituting the value of $y$ in equation (1) we get:

$x=\frac{7.05-5y}{4}$

$x=\frac{7.05-5\times 0.85}{4}$

$x=\frac{7.05-4.25}{4}$

$x=\frac{2.8}{4}$

$x=0.70.$

The cost of a piece of dark meat = $0.70.

Therefore, the cost of a piece of dark meat is $0.70 and the cost of a piece of white meat is $0.85.

5 0

3 years ago