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RoseWind [281]
3 years ago
8

Harold collected data on the daily high temperature in two cities over a period of one week.

Mathematics
1 answer:
Misha Larkins [42]3 years ago
3 0

Answer:

Correct choices are 1 and 4

Step-by-step explanation:

As per data given we have:

  • Median temperature is 75°F and 88°F
  • And the range from the median is 5° for both cities

This gives us lowest temperatures of:

  • 75° -5° = 70° and 88° - 5°= 83° respectively

And high temperatures are:

  • 75° + 5° = 80° and 88° + 5° = 93°

<u>Answer choices based on above details:</u>

  • Choice 1 - correct
  • Choice 2 - incorrect. Correct answer is 93°
  • Choice 3 - incorrect. Correct answer is 93° - 70° = 23°
  • Choice 4 - correct

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what does it mean to be a function how can you determine functionality of a relation or eqaution graph
mylen [45]
Determining whether a relation is a function on a graph is relatively easy by using the vertical line test. If a vertical line crosses the relation on the graph only once in all locations, the relation is a function. However, if a vertical line crosses the relation more than once, the relation is not a function.
3 0
2 years ago
(83.9x10^12)(2.87x10^-3)/ 3.76x10^2
RideAnS [48]
<u>(83.9 × 10^12)(2.87 × 10^-³)</u>
             3.76 × 10²
<u>(83,900,000,000,000)(0.00287)</u>
                   376
 <u>240,793,000,000</u>                                 
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640,406,914.9


8 0
3 years ago
The weekly amount spent by a small company for in-state travel has approximately a normal distribution with mean $1450 and stand
Llana [10]

Answer:

0.0903

Step-by-step explanation:

Given that :

The mean = 1450

The standard deviation = 220

sample mean = 1560

P(X > 1560) = P( Z > \dfrac{x - \mu}{\sigma})

P(X > 1560) = P(Z > \dfrac{1560 - 1450}{220})

P(X > 1560) = P(Z > \dfrac{110}{220})

P(X> 1560) = P(Z > 0.5)

P(X> 1560) = 1 - P(Z < 0.5)

From the z tables;

P(X> 1560) = 1 - 0.6915

P(X> 1560) = 0.3085

Let consider the given number of weeks = 52

Mean \mu_x = np = 52 × 0.3085 = 16.042

The standard deviation =  \sqrt {n \time p (1-p)}

The standard deviation = \sqrt {52 \times 0.3085 (1-0.3085)}

The standard deviation = 3.3306

Let Y be a random variable that proceeds in a binomial distribution, which denotes the number of weeks in a year that exceeds $1560.

Then;

Pr ( Y > 20) = P( z > 20)

Pr ( Y > 20) = P(Z > \dfrac{20.5 - 16.042}{3.3306})

Pr ( Y > 20) = P(Z >1 .338)

From z tables

P(Y > 20) \simeq 0.0903

7 0
3 years ago
Which expression is equivalent to 24 ⋅ 2−7?
marta [7]

Answer:

211

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
What multiplies to 16 and adds to negative 12
Romashka-Z-Leto [24]
Factor 16 and see the - factor pairs and add them, see which add to -12
-1-16=-17 nope
-2-8=-10 nope
-4-4=-8
hmm


we will solve with math
xy=16
x+y=-12
minus  x both sides
y=-12-x
sub for y in other equation
x(-12-x)=16
-12x-x^2=16
add 12x+x^2 both sides
0=x^2+12x+16
use quadratic formula
if you have
ax^2+bx+c=0
x=\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}


0=x^2+12x+16
a=1
b=12
c=16

x=\frac{-12+/- \sqrt{12^{2}-4(1)(16) }}{2(1)}
x=\frac{-12+/- \sqrt{144-64 }}{2}
x=\frac{-12+/- \sqrt{80}}{2}
x=\frac{-12+/- 4\sqrt{5}}{2}
x=\frac{-6+/- 2\sqrt{5}
x=\frac{-6+ 2\sqrt{5} or \frac{-6- 2\sqrt{5}

aprox
x=-1.52786 or -10.4721

those are the numbers

the numbes are -1.52786 or -10.4721

6 0
3 years ago
Read 2 more answers
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