Alright! So to solve these questions, you need to find out the difference. You can use ratios to solve this. For example, question #25:
A class had 30 pupils at the beginning of this school term, but now has 5 more pupils. What is the percent of increase?
The question is basically asking how much 5 is in ratio to 30. So just divide 5 (the given amount) by 30 (the total amount). The answer is 0.16, or 16%
132/2 = 66
66/2 = 33
33/3 = 11
11/11 = 1
132 = 2^2 * 3 * 11
55121/11 = 5011
5011/5011 = 1
55,121 = 11 * 5011
LCM = common factor with larger exponent * not common factors
LCM = 2^2 * 3 * 11 * 5011
LCM = 661,452
Answer:
4.80 mm to 2 d.p
Step-by-step explanation:
w = f(r)
f'(r) = (dw/dr) = (0.0218 mm/mm)
So, for a small difference in rainfall of 220 mm, what is the corresponding small difference in width of leaves in the two forests given.
One definition of a derivative or a rate of change is that it is the ratio of very small differences in the dependent variable to very small differences in the independent variable.
Mathematically,
(dw/dr) = (Δw/Δr) for very small Δw and Δr.
0.0218 = (Δw/220)
Δw = 0.0218 × 220 = 4.796 mm = 4.80 mm to 2 d.p
Hope this Helps!!!
Answer:
t=7,t=0
Step-by-step explanation:
2t^2-14t+3=3
Subtract 3 from both sides
2t^2 - 14t +3 - 3 = 3-3
Simpilfy
2t^2 -14t = 0
Answer:
- 3/4
Step-by-step explanation:
m = difference of y / difference of x = (3 - (-3)) / (-5 -3) = 6 / -8 = - 3 / 4
