Answer:
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A square since all sides are equal and the angles aren't acute so it can't be a rhombus
Answer:
P(A∣D) = 0.667
Step-by-step explanation:
We are given;
P(A) = 3P(B)
P(D|A) = 0.03
P(D|B) = 0.045
Now, we want to find P(A∣D) which is the posterior probability that a computer comes from factory A when given that it is defective.
Using Bayes' Rule and Law of Total Probability, we will get;
P(A∣D) = [P(A) * P(D|A)]/[(P(A) * P(D|A)) + (P(B) * P(D|B))]
Plugging in the relevant values, we have;
P(A∣D) = [3P(B) * 0.03]/[(3P(B) * 0.03) + (P(B) * 0.045)]
P(A∣D) = [P(B)/P(B)] [0.09]/[0.09 + 0.045]
P(B) will cancel out to give;
P(A∣D) = 0.09/0.135
P(A∣D) = 0.667
Answer:
1. x =0; x = -7
2. x = -3; x = 10
3. x = -5; x = -4
Step-by-step explanation:
(1). 6x² + 42x = 0
6x (x + 7) = 0
6x = 0. OR. x + 7 = 0
x = 0/6. x = 0 - 7
x = 0. x = -7
x = 0
x = -7
(2). x² - 7x - 30 = 0
The factors here are (3, -10)
x² - 10x + 3x - 30 = 0
x ( x - 10) + 3 ( x - 10) = 0
(x + 3) ( x - 10) = 0
x + 3 = 0 OR. x - 10 = 0
x = 0-3. x = 0 + 10
x = -3. x = 10
x = -3
x = 10
(3). x² + 9x + 20 = 0
The factors are ( 4, 5)
x² + 4x + 5x + 20 = 0
x ( x + 4) + 5 ( x + 4) = 0
(x + 5) (x + 4) = 0
x + 5 = 0 . OR. x + 4 = 0
x = 0-5. x = 0 - 4
x = -5. x = -4
x = -5
x = -4
The answer to this question is:
y = -2x - 1
