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gavmur [86]
3 years ago
15

Milley wants to solve the following equations using the method of elimination:

Mathematics
1 answer:
timurjin [86]3 years ago
3 0
She should multiply y = x - 2 by -4...that way one x will be -4x and the other will be 4x   and they will cancel out when added.

answer is -4
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Answer:

D: There were 100 more football players than basketball players.

Step-by-step explanation:

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2 years ago
Define variables and write a system of equations for each situation. Solve by using substitution.Suppose you want to join a vide
MrRa [10]

Answer:

The cost is the same after 15 video rentals

Step-by-step explanation:

Let the total cost be y

Let the number of video rentals made be x

Discount card for Big video = $9.99

Discount card for Main Street video = $20.49

Cost of 1 big video rental = $2.49

Cost of 1 Main Street video rental = $1.79

Cost of video rentals with big video:

Y = 9.99 + 2.49x………….(1)

Cost of video rentals with main street video :

Y = 20.49 +1.79x…………(2)

For the two costs to be equal, the two equations have to be equal to each other

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9.99 + 2.49x = 20.49 +1.79x

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X = 10.5/0.7

X = 15  video rentals

8 0
3 years ago
So do you know ughhh
Sauron [17]
The answer is 6 i hope this helped you
7 0
3 years ago
Camden is going to invest $600 and leave it in an account for 12 years. Assuming the
UkoKoshka [18]

~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & \$920\\ P=\textit{original amount deposited}\dotfill & \$600\\ r=rate\to r\%\to \frac{r}{100}\\ t=years\dotfill &12 \end{cases}

920=600e^{\frac{r}{100}\cdot 12}\implies \cfrac{920}{600}=e^{\frac{3r}{25}}\implies \cfrac{23}{15}=e^{\frac{3r}{25}}\implies \log_e\left( \cfrac{23}{15} \right)=\log_e\left( e^{\frac{3r}{25}} \right) \\\\\\ \ln\left( \cfrac{23}{15} \right)=\cfrac{3r}{25}\implies 25\cdot \ln\left( \cfrac{23}{15} \right)=3r\implies \cfrac{25\cdot \ln\left( \frac{23}{15} \right)}{3}=r \\\\\\ 3.5620\approx r\implies \stackrel{\%}{3.56}\approx r

7 0
2 years ago
Consider the surface f (x comma y comma z )f(x,y,z)equals=negative 2 x squared plus 2 y squared minus 3 z squared plus 3 equals
trapecia [35]

Answer:

a) (8,8,-6)

b) 4x+4y+3z = -3

Step-by-step explanation:

a)

The surface is given by the equation  

f(x,y,z) = 0 where

f(x,y,z)=-2x^2+2y^2-3z^2+3

The gradient of this function is the vector

(\frac{\partial f}{\partial x},\frac{\partial f}{\partial y},\frac{\partial f}{\partial z})=(-4x,4y,-6z)

If we evaluate it in the point P = (-2,2,1) we obtain the point

(8,8,-6)

b)

The vectors with their tails at P are of the form  

(-2,2,1)-(x,y,z) = (-2-x, 2-y, 1-z)

as they must be orthogonal to the gradient, they must be orthogonal to the vector (8,8,6) so their inner product is 0

(-2-x,2-y,1-z)\cdot(8,8,6)=0\Rightarrow -16-8x+16-8y+6-6z=0\Rightarrow 4x+4y+3z=-3

and the equation of the desired plane is

4x+4y+3z = -3

3 0
3 years ago
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