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raketka [301]
3 years ago
9

What is the product of z1 and z2 if z1 = 2(cos70° + i sin70°) and z2 = 4(cos200° + i sin200°)?

Mathematics
1 answer:
Nookie1986 [14]3 years ago
4 0

Answer:

<u><em>8(cos270° + i sin270°)</em></u>

Step-by-step explanation:

(cos(a) + i * sin(a)) * (cos(b) + i * sin(b)) = cos(a + b) = i * sin(a + b)

2 * 4 * (cos(270) + i * sin(270))

8(cos270° + i sin270°)

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strojnjashka [21]

Answer:

x+y=5

Step-by-step explanation:

y=-x+5

add x to both sides

x+y=5

8 0
3 years ago
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Mike deposited $6500 into two saving accounts bearing simple interest. One of the accounts has an interest rate of 3% while the
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0.03x+0.06 (6500-x)=225
Solve for x
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3 years ago
Expand and simplify (x + 11)(x + 11)
labwork [276]

Answer:

Expand: x² + 11x + 11x + 121

Simplify: x² + 22x + 121

Step-by-step explanation:

To expand this, you can use the FOIL technique:

First terms

Outer terms

Inner terms

Last terms

(x+11)(x+11)

F - x*x = x²

O - x*11 = 11x

I - 11*x = 11x

L - 11*11 = 121

Put these numbers together (expanded) to get:

x² + 11x + 11x + 121

Put the common terms together (simplify) to get:

x² + 22x + 121

Note:

Not sure if you need this info, but (x + 11)(x + 11) is the same as (x + 11)².

The numbers need to be in the order I put them in because you are supposed to place them in order greatest to least degree.

Hope it helps!

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