Question

In the equation (x+2)^2+(y-3)^2=4, the radius of the circle is

Answer 1

Answer:

center = (-2, 3)

radius = 2

Step-by-step explanation:

(x+2)^2   +  (y-3)^2 =  4

Use the formula:   (x - h)^2   +  (y - k)^2  = r^2

where (h, k) = center,   radius = r

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(x - (-2))^2   +  (y - 3)^2 =  4 =  (2)^2

center = (-2, 3)

radius = 2