Answer:
The amount that would be in the account after 30 years is $368,353
Step-by-step explanation:
Here, we want to calculate the amount that will be present in the account after 30 years if the interest is compounded yearly
We proceed to use the formula below;
A = [P(1 + r)^t-1]/r
From the question;
P is the amount deposited yearly which is $4,500
r is the interest rate = 2.5% = 2.5/100 = 0.025
t is the number of years which is 30
Substituting these values into the equation, we have;
A = [4500(1 + 0.025)^30-1]/0.025
A = [4500(1.025)^29]/0.025
A = 368,353.3309607034
To the nearest whole dollars, this is;
$368,353
Answer:
2 x^2 - 3 x + 6
Step-by-step explanation:
Simplify the following:
-(3 x^2 + 4 x - 17) + 5 x^2 + x - 11
-(3 x^2 + 4 x - 17) = -3 x^2 - 4 x + 17:
-3 x^2 - 4 x + 17 + 5 x^2 + x - 11
Grouping like terms, 5 x^2 - 3 x^2 + x - 4 x - 11 + 17 = (5 x^2 - 3 x^2) + (x - 4 x) + (-11 + 17):
(5 x^2 - 3 x^2) + (x - 4 x) + (-11 + 17)
5 x^2 - 3 x^2 = 2 x^2:
2 x^2 + (x - 4 x) + (-11 + 17)
x - 4 x = -3 x:
2 x^2 + -3 x + (-11 + 17)
17 - 11 = 6:
Answer: 2 x^2 - 3 x + 6
For this fraction, you would have to see how many times 7 goes into 47. So, 6 times as 7 times 6 is 42. Subtract 42 from 47, and this would be your remainder:
6
Answer:
x=90 degree
y=30 degree
Step-by-step explanation:
Answer:
slope: -1
y intercept= 0,5
equation: y= -x+5
Step-by-step explanation:
