Answer:
![\boxed{\text{20.2 mL}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Ctext%7B20.2%20mL%7D%7D)
Explanation:
Assume that the volume of the stock solution is 1 L.
1. Mass of stock solution
![\text{Mass} = \text{1000 mL} \times \dfrac{\text{0.8990 g}}{\text{1 mL}} = \text{899.0 g}](https://tex.z-dn.net/?f=%5Ctext%7BMass%7D%20%3D%20%5Ctext%7B1000%20mL%7D%20%5Ctimes%20%5Cdfrac%7B%5Ctext%7B0.8990%20g%7D%7D%7B%5Ctext%7B1%20mL%7D%7D%20%3D%20%5Ctext%7B899.0%20g%7D)
2.Mass of NH₃
![\text{Mass of NH}_{3} = \text{899.0 g stock} \times \dfrac{\text{28.2 g NH}_{3}}{\text{100 g stock}} = \text{253.5 g NH}_{3}](https://tex.z-dn.net/?f=%5Ctext%7BMass%20of%20NH%7D_%7B3%7D%20%3D%20%5Ctext%7B899.0%20g%20stock%7D%20%5Ctimes%20%5Cdfrac%7B%5Ctext%7B28.2%20g%20NH%7D_%7B3%7D%7D%7B%5Ctext%7B100%20g%20stock%7D%7D%20%3D%20%5Ctext%7B253.5%20g%20NH%7D_%7B3%7D)
3. Moles of NH₃
![\text{Moles of NH}_{3} = \text{253.5 g NH}_{3}\times \dfrac{\text{1 mol NH}_{3}}{\text{17.03 g NH}_{3}}= \text{14.89 mol NH}_{3}](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20NH%7D_%7B3%7D%20%3D%20%5Ctext%7B253.5%20g%20NH%7D_%7B3%7D%5Ctimes%20%5Cdfrac%7B%5Ctext%7B1%20mol%20NH%7D_%7B3%7D%7D%7B%5Ctext%7B17.03%20g%20NH%7D_%7B3%7D%7D%3D%20%5Ctext%7B14.89%20mol%20NH%7D_%7B3%7D)
4. Molar concentration of stock solution
![c = \dfrac{\text{moles}}{\text{litres}} = \dfrac{\text{14.89 mol}}{\text{1 L}} = \text{14.89 mol/L}](https://tex.z-dn.net/?f=c%20%3D%20%5Cdfrac%7B%5Ctext%7Bmoles%7D%7D%7B%5Ctext%7Blitres%7D%7D%20%3D%20%5Cdfrac%7B%5Ctext%7B14.89%20mol%7D%7D%7B%5Ctext%7B1%20L%7D%7D%20%3D%20%5Ctext%7B14.89%20mol%2FL%7D)
5. Volume of stock needed for dilution
Now that you know the concentration of the stock solution, you can use the dilution formula .
![c_{1}V_{1} = c_{2}V_{2}](https://tex.z-dn.net/?f=c_%7B1%7DV_%7B1%7D%20%3D%20c_%7B2%7DV_%7B2%7D)
to calculate the volume of stock solution.
Data:
c₁ = 14.89 mol·L⁻¹; V₁ = ?
c₂ = 0.500 mol·L⁻¹; V₂ = 600 mL
Calculations:
![\begin{array}{rcl}14.89V_{1} & = & 0.500 \times 600\\14.89V_{1} & = & 300\\V_{1} & = & \text{20.2 mL}\\\end{array}\\\text{You will need $\boxed{\textbf{20.2 mL}}$ of the stock solution.}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Brcl%7D14.89V_%7B1%7D%20%26%20%3D%20%26%200.500%20%5Ctimes%20600%5C%5C14.89V_%7B1%7D%20%26%20%3D%20%26%20300%5C%5CV_%7B1%7D%20%26%20%3D%20%26%20%5Ctext%7B20.2%20mL%7D%5C%5C%5Cend%7Barray%7D%5C%5C%5Ctext%7BYou%20will%20need%20%24%5Cboxed%7B%5Ctextbf%7B20.2%20mL%7D%7D%24%20of%20the%20stock%20solution.%7D)
Mg(s) + 2 AgNO₃(aq) = Mg(NO₃)₂(aq) + 2 Ag(s)
reaction is :<span> single replacement
hope this helps!</span>
1)water has a great capacity to hold a moderate heat energy
Answer:
Chemicals
Explanation:
Your answer would be chemicals because of you have different inputs you would also have a different output depending.
I hope it helps! Have a great day!
Anygays-
Far away from the atom because think of it like a magnet. Nucleus is positive charge while Electron is negative charge. Put opposite charges together like a magnet its going to attract and take some effort to separate them. Now put two opposite charge a foot away from each other, you should be able to move it no problem.