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Pavel [41]
3 years ago
9

Hamid made this table to organize his notes on the properties of acids and bases.

Chemistry
2 answers:
Molodets [167]3 years ago
8 0

Answer : The property in the wrong column is, base form hydrogen gas with metals

Explanation :

Acid : It is a substance that has ability of donating a proton or hydrogen ion, H^+.

The properties of an acid are :

  • Acids are sour in taste.
  • It conduct electricity.
  • The texture of an acid solution is sticky.
  • It react with carbonates to give salt.
  • It changes the color of the litmus paper to red.
  • It react with a metal to give compound and hydrogen gas.

Base : It is a substance that has ability of donating hydroxide ion, OH^-.

The properties of an base are :

  • Base are bitter in taste.
  • It conduct electricity.
  • The texture of an base solution is slippery.
  • It changes the color of the litmus paper to blue.
  • It does not react with a metal.

Hence, from the above information, we conclude that the property in the wrong column is, base form hydrogen gas with metals .

Ugo [173]3 years ago
7 0

Answer:

from hydrogen gas with metals

Explanation:

short cut answer :)

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Will a precipitate of magnesium fluoride form when 300. mL of 1.1 × 10 –3 M MgCl 2 are added to 500. mL of 1.2 × 10 –3 M NaF? [K
Tju [1.3M]

Answer:

No precipitate is formed.

Explanation:

Hello,

In this case, given the dissociation reaction of magnesium fluoride:

MgF_2(s)\rightleftharpoons Mg^{2+}+2F^-

And the undergoing chemical reaction:

MgCl_2+2NaF\rightarrow MgF_2+2NaCl

We need to compute the yielded moles of magnesium fluoride, but first we need to identify the limiting reactant for which we compute the available moles of magnesium chloride:

n_{MgCl_2}=0.3L*1.1x10^{-3}mol/L=3.3x10^{-4}molMgCl_2

Next, the moles of magnesium chloride consumed by the sodium fluoride:

n_{MgCl_2}^{consumed}=0.5L*1.2x10^{-3}molNaF/L*\frac{1molCaCl_2}{2molNaF} =3x10^{-4}molMgCl_2

Thus, less moles are consumed by the NaF, for which the moles of formed magnesium fluoride are:

n_{MgF_2}=3x10^{-4}molMgCl_2*\frac{1molMgF_2}{1molMgCl_2}=3x10^{-4}molMgF_2

Next, since the magnesium fluoride to magnesium and fluoride ions is in a 1:1 and 1:2 molar ratio, the concentrations of such ions are:

[Mg^{2+}]=\frac{3x10^{-4}molMg^{+2}}{(0.3+0.5)L} =3.75x10^{-4}M

[F^-]=\frac{2*3x10^{-4}molMg^{+2}}{(0.3+0.5)L} =7.5x10^{-4}M

Thereby, the reaction quotient is:

Q=(3.75x10^{-4})(7.5x10^{-4})^2=2.11x10^{-10}

In such a way, since Q<Ksp we say that the ions tend to be formed, so no precipitate is formed.

Regards.

6 0
3 years ago
Awit pildi sa ml lol​
Anuta_ua [19.1K]

Answer:

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In science class, Jonathan added a small amount of sand to a beaker of water. He stirred it vigorously so that all the sand swir
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3 years ago
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If a substance cannot be broken down chemically into a simpler substance what is it
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Answer: An Element

Explanation:

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Explanation:

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A double displacement reaction in which one of the product is formed as a solid is called as precipitation reaction.  

The balanced chemical equation is:

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