A central atom has two lone pairs on opposite sides and four single bonds. What is the molecule geometry of the result?

Chemistry

1 answer:

ryzh [129]3 years ago

8 0

The molecular geometry is square planar.

According to the Valence Shell Electron Pair Repulsion theory (VSEPR), the shape of a molecule is determined by the number of valence electrons surrounding the outermost shell of the central atom in the molecule.

In this case, the expected geometry based on VSEPR theory is octahedral. However, the lone pairs on opposite sides of the four single bonds leads to a square planar molecular geometry.

Learn more; brainly.com/question/24396703

You might be interested in

How many outer planets are there?

Ivenika [448]

Answer:

four outer planetsThe Outer Planet the four outer planets and the Sun, with sizes to scale. From left to right, the outer planets are Jupiter, Saturn, Uranus, and Neptune. The gas giants are mostly made of hydrogen and helium. These are the same elements that make up most of the Sun.

Explanation:

I hope this helps you

Ari

mwah

3 0

2 years ago

Uranium in the isotope below had 140 nutrons

Brut [27]

Answer:

It has 140 neutrons because Mass number= No of protons + no of neutrons

4 0

3 years ago

On the seashore pebbles that are rough and uneven become smooth and rounded explain how they become smooth and rounded

Andru [333]

The pebbles become smooth and even because of erosion. the waves from the sea rub against the pebbles this is erosion. x

7 0

3 years ago

Nickel and carbon monoxide react to form nickel carbonyl, like this: (s)(g)(g) At a certain temperature, a chemist finds that a

horsena [70]

The question is incomplete, here is the complete question:

Nickel and carbon monoxide react to form nickel carbonyl, like this:

$Ni(s)+4CO(g)\rightarrow Ni(CO)_4(g)$

At a certain temperature, a chemist finds that a 2.6 L reaction vessel containing a mixture of nickel, carbon monoxide, and nickel carbonyl at equilibrium has the following composition:

Compound Amount

Ni 12.7 g

CO 1.98 g

$Ni(CO)_4$ 0.597 g