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Serga [27]
3 years ago
13

A central atom has two lone pairs on opposite sides and four single bonds. What is the molecule geometry of the result?

Chemistry
1 answer:
ryzh [129]3 years ago
8 0

The molecular geometry is square planar.

According to the Valence Shell Electron Pair Repulsion theory (VSEPR), the shape of a molecule is determined by the number of valence electrons surrounding the outermost shell of the central atom in the molecule.

In this case, the expected geometry based on VSEPR theory is octahedral. However, the lone pairs on opposite sides of the four single bonds leads to a square planar molecular geometry.

Learn more; brainly.com/question/24396703

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(i)Draw an arrow to show the activation energy on the diagram.
leonid [27]

Answer:

Explanation:

(i) Image

(ii) The energy of the products is more than that of the reactants, which shows that energy was absorbed. Hence, the reaction is endothermic.

8 0
2 years ago
At 900 K the following reaction has Kp=0.345: 2SO2(g)+O2(g)ââ2SO3(g) In an equilibrium mixture the partial pressures of SO2 and
rjkz [21]

Answer: 1.58\times 10^{-3}atm

Explanation:

Equilibrium constant is the ratio of the concentration of products to the concentration of reactants each term raised to its stochiometric coefficients.

The given balanced equilibrium reaction is,

               2SO_2(g)+O_2(g)\rightleftharpoons 2SO_3(g)       The expression for equilibrium constant for this reaction will be,

K_p=\frac{(p_{SO_3})^2}{(p_{SO_2})^2(p_{O_2})}

Now put all the given values in this expression, we get :

0.345=\frac{(p_{SO_3})^2}{(0.125)^2(0.470)}

p_{SO_3}=1.58\times 10^{-3}atm

Thus the equilibrium partial pressure of SO_3 in the mixture is 1.58\times 10^{-3}atm

3 0
3 years ago
Ammonia (NH3) can be synthesized from nitrogen gas (N2) and hydrogen gas (H2) by the following reaction.
Advocard [28]

Answer:

                      %age Yield  =  66.05 %

Explanation:

                     In order to check the efficiency of a reaction the %age is calculated so that it can be concluded that either the conditions provided for certain reactions are favourable or not because at large scales reactions with greater %age yields are favoured as it results in high product quantity and hence, greater economical advantages.

                   The percent yield is given as;

                  %age Yield  =  Actual Yield / Theoretical Yield × 100

Putting values,

                   %age Yield  =  253 g / 383 g × 100

                   %age Yield  =  66.05 %

Hence, for the given reaction the success of the reaction is only 65% hence, steps can be made to improve this yield by modifying the reaction conditions.

6 0
3 years ago
Please help <br> with this question
ikadub [295]
First square to the right
4 0
3 years ago
Read 2 more answers
Write a balanced chemical equation for the fermentation sucrose (C12H22O11) by yeasts in which the aqueous ethyl alcohol (C2H5OH
kodGreya [7K]

Answer:

C12H22O11(aq) + H2O(l) —> 4C2H5OH(aq) + 4CO2(g)

Explanation:

When aqueous sugar (sucrose) react with water in the presence of yeast, the following products are obtained as shown in the equation below:

C12H22O11(aq) + H2O(l) —> C2H5OH(aq) + CO2(g)

Now, we shall balance the equation as follow:

There are a total of 24 atoms of H on the left side and 6 atoms on the right side. It can be balance by putting 4 in front of C2H5OH as shown below:

C12H22O11(aq) + H2O(l) —> 4C2H5OH(aq) + CO2(g)

There are a total of 9 atoms of C on the right side and 12 atoms on the left side. It can be balance by putting 4 in front of CO2 as shown below:

C12H22O11(aq) + H2O(l) —> 4C2H5OH(aq) + 4CO2(g)

Now the equation is balanced.

8 0
3 years ago
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