Y = x2 – 3x – 10
roots are x intercepts on form of (x,0)
Let's solve the quadratic equation
y = x2 – 3x – 10
(x-5)(x+2)
x=5,-2
roots: (5,0)(-2,0)
let's see of these are correct
y = x2 – 3x – 10
y=(5)^2-3 (5)-10
y=25-15-10
y=10-10
y=0
y = x2 – 3x – 10
y=(-2)^2-3 (-2)-10
y=4+6-10
y=10-10
y=0
the roots are correct
7+x^3. It cannot be simplified further without knowing the value of x
The distance around the edge of a shape
Base times height times width