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photoshop1234 [79]
3 years ago
7

Can someone PLEASE HELP ME ASAP

Mathematics
2 answers:
stepan [7]3 years ago
8 0
11 hours because you cross multiply and then divide by 60 since time
Vlad [161]3 years ago
7 0

Answer: The correct answer for number 1. is 11




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What is the answer to 2x3x42dividex3x2
LuckyWell [14K]
Cleary it fits 1 2/3 3/5 more than twice
3 0
3 years ago
Can someone do these? xD
Alenkinab [10]
16 = G + C
C = G - 6
16 = G + G - 6
16 = 2G - 6
22 = 2G
11 = G
G = 11


20 = B + K
B = 3K
20 = 3K + K
20 = 4K
5 = K
20 - 5 = 15
B = 15
3 0
3 years ago
It is known that 10% of the items produced by a certain machine end up having a flaw. If we select 7 items from the production l
denpristay [2]

Step-by-step explanation:

p = 0.1, q = 0.9, n = 7

a) Use complementary probability.

P(at least 1) = 1 − P(0)

P(at least 1) = 1 − (0.9)⁷

P(at least 1) = 0.522

b) Use binomial probability.

P = nCr pʳ qⁿ⁻ʳ

P(3) = ₇C₃ (0.1)³ (0.9)⁴

P(3) = 0.023

6 0
3 years ago
A triangle has sides with lengths of 11 miles, 15 miles, and 17 miles. Is it a right triangle?​
dybincka [34]

Answer:

Below.

Step-by-step explanation:

If its a right triangle it will obey the Pythagoras theorem.

17^2 = 289

11^2 + 15^2 = 121 + 225  = 346

- so NOT a right triangle.

3 0
3 years ago
A quality control inspector has drawn a sample of 19 light bulbs from a recent production lot. If the number of defective bulbs
Inessa05 [86]

Answer:

0.0016283

Step-by-step explanation:

Given that:

Proportion of defective bulbs, p = 30% = 0.3

Sample size, n = 19 bulbs

Probability that the lot will pass inspection :

P(none of the 19 is defective) Or P(only one of the 19 is defective)

P(none of the 19 is defective) = (1 - p) ^n = (1 - 0.3)^19 ; 0.7^19

0.7^19 = 0.0011398

P(only one of the 19 is defective) :

P(1 defective) * P(18 not defective )

(0.3) * (1 - 0.3)^18

0.3 * 0.7^18

0.3 * 0.001628413597910449 = 0.0004885

Hence,

P(none of the 19 is defective) + P(only one of the 19 is defective)

0.0011398 + 0.0004885) = 0.0016283

8 0
3 years ago
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