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3 years ago

PLEASE HELP ME, ILL BRAINLIEST YOU ill give u 30 points if you help

Mathematics

2 answers:

lisov135 [29]3 years ago

7 0

Answer:

$x = 58$

$y = 90$

Step-by-step explanation:

This is a rhombus becuase it a quadralterial and it has four right triangles, and it diagonals bisect each others so it cant be a trapezoid, and paralleolgram. and it doesnt have four right corner angles so it cant be a square or rectangle or kite.

A rhombus inner angle measure is 90 degrees.

$y = 90$

This means the upper left angle of the top triangle measure is 58 becuase triangle interior theorem.

Since a rhombus bisects angles, angle x measure 58.

blondinia [14]3 years ago

3 0

PLEASEEEEE CAN SOMEONE HELP MEEE??? (iI have TWO questions PLSPLSPLSPSLPLSPLSPLSP)

3.) What happened to Patroclus at the end of yesterday's reading?

He won the battle.

He went to Mt. Olympus to talk to Zeus.

He died.

-------------------------------------------------------------------------------------------------------

4.Who was Agamemnon trying to persuade to come fight with him again?

Patroclus

Achilles

Odysseus

Hector

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Answer:

$\displaystyle \frac{100}{81}m^8p^{12}q^{16}z^2-\frac{20}{63}m^5p^7q^8z^5+ \frac{1}{49}m^2p^2z^8=\left(\frac{10}{9}m^4p^{6}q^{8}z-\frac{1}{7}mpz^4\right)^2$

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* El último término es un cuadrado perfecto

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$\displaystyle b=\sqrt{\frac{1}{49}m^2p^2z^8$

$\displaystyle b=\frac{1}{7}mpz^4$

Nos cercioramos de que el término central es 2ab:

$\displaystyle 2ab=2\frac{10}{9}m^4p^{6}q^{8}z\frac{1}{7}mpz^4$

Operando:

$\displaystyle 2ab=\frac{20}{63}m^5p^7q^8z^5$

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$\displaystyle \frac{100}{81}m^8p^{12}q^{16}z^2-\frac{20}{63}m^5p^7q^8z^5+ \frac{1}{49}m^2p^2z^8=\left(\frac{10}{9}m^4p^{6}q^{8}z-\frac{1}{7}mpz^4\right)^2$

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