The speed of the car is 60 m/s
Explanation:
The speed of an object is a scalar quantity telling "how fast" the object is moving, regardless of its direction. It can be calculated as follows:
where
d is the distance covered
t is the time taken
For the car in this problem, we have
is the distance covered
is the time taken
Subsituting into the equation, we find the speed:
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Answer:
V = 308.1 m/s θ = -64º
Explanation:
a and b) We will use the projectile launch equations where we are asked to find the speed when the tank reaches the ground
Let's start by breaking down the speed
Vox = Vo cos θ
Voy = Vo sint θ
Vox = 140 cos 15 = 135.2 m / s
Voy = 140 sin 15 = 36.2 m / s
Let's look for vertical speed when it hits the ground
Vy² = Voy² - 2gy
Vy = √(36.2² - 2 9.8 3.98 103) = √ (1310-78008)
Vy = 276.9 m / s
We have both components.
V² = Vx² + Vy²
V = √ (135.2² + 276.9²)
V = 308.1 m / s
tan θ = Vy / Vx
tan θ = -276.9 / 135.2 = 2,048
θ = -64º
The negative sign means that it is measured from the x-axis clockwise
c and d) We repeat the same calculation for tank B, the only difference is the angle T = -15º
Vox = 140 cos (-15)
Voy = 140 sin (-15)
Vox = 135.2 m / s
Voy = 140 sin (-15)
Voy = -36.2 m / s
We calculate the vertical speed
Vy² = Voy² - 2 g Y
Vy = √ ((-36.2)² - 2 9.8 3980)
Vy = 276.9 m / s
V = √(135.3²2 + 276.9²)
V = 308.1 m/s
tan θ = -276.9 / 135.2
θ = -64
You can see that the speeds and angles are the same in both cases, the difference between these two situations is in the horizontal distance that runs each story
Displacement is the area under the velocity/time graph. So for example this object's displacement in the first 3 seconds is (1/2)(3sec)(12.5 m/s)= 18.75m. (and then it starts backing up, displacement decreasing, after 3sec when velocity is negative).
But This object is never speeding up. Its velocity is smoothly decreasing at (25/6) m/s^2 (the slope of the graph). So the answer to the question is actually zero.
Answer:
A green object will absorb all light except for green light and reflect blue and yellow light.
From the word compound, the compound machine is already a combination of two or more types of simple machine. Thus, the answer is letter C. Because of its complexity, it is able to perform several other functions than a simple one.