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Arturiano [62]
3 years ago
7

What can accurately be said about a resultant wave that displays both reinforcement and interference? A. The component waves hav

e different frequencies. B. Maximum interference occurs where the troughs of the two component waves are in phase. C. Molecules remain in their normal positions at spots of reinforcement. D. The crests of the two component waves are in phase where interference occurs in the resultant wave. Mark for review (Will be highlighted on the review page)
Physics
2 answers:
Agata [3.3K]3 years ago
7 0
<h3><u>Answer;</u></h3>

A. The component waves have different frequencies.

<h3><u>Explanation;</u></h3>
  • <em><u>interference is one of the property of waves that occurs when  two waves superpose to form a resultant wave of greater, lower, or the same amplitude.</u></em>
  • Interference occurs when two waves travelling in the same medium at the same time. It may be either a constructive or a destructive interference.
  • <em><u>Constructive interference occurs when the two waves are in phase and have the same frequency, the amplitudes are therefore, reinforced resulting to a constructive interference.</u></em> However, if the two waves are out phase the result will be a destructive interference.
Tanya [424]3 years ago
4 0
The answer is A. <span>The component waves have different frequencies.
The magnitudes of reinforcement usually really dependent on the number of frequencies and interference is usually caused due to the difference in frequencies. So, we can conclude that if the frequencies are different and causing interference, the reinforcement will also different
</span>
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The black squirrel has zero kinetic energy (if it's not moving) and lower gravitational potential energy than the red squirrel or zero gravitational potential energy if the ground is assumed to be zero gravitational potential line.

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Statement A: Area of a rectangle with measured length = 2.536 mm and width = 1.4 mm.
pochemuha

Explanation:

Formula for calculating the area of a  rectangle A = Length *width

For statement A;

Given area of a rectangle with measured length = 2.536 mm and width = 1.4 mm.

Area of the rectangle = 2.536mm * 1.4mm

Area of the rectangle = 3.5504mm²

The rule of significant figures states that we should always convert the answer to the least number of significant figure amount the given value in question. Since 1.4mm has 2 significant figure, hence we will convert our answer to 2 significant figure.

Area of the rectangle = 3.6mm² (to 2sf)

For statement B;

Given area of a rectangle with measured length = 2.536 mm and width = 1.41 mm.

Area of the rectangle = 2.536mm * 1.41mm

Area of the rectangle = 3.57576mm²

Similarly, Since 1.41mm has 3 significant figure compare to 2.536 that has 4sf, hence we will convert our answer to 3 significant figure.

Area of the rectangle = 3.58mm² (to 3sf)

Based on the conversion, it can be seen that 3.6mm²  is greater than 3.58mm², hence the area of rectangle in statement A is greater than the area of the rectangle in statement B.

7 0
3 years ago
When two waves collide and create a taller wave, what interference occurs?
oksano4ka [1.4K]

It would be Constructive interference. It occurs when two waves collide and make a taller wave. 
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3 years ago
A baseball player friend of yours wants to determine his pitching speed. You have him stand on a ledge and throw the ball horizo
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Answer:

v_{ox}= 19.6\ m/s

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Initial vertical velocity= v_{oy}  (Since ball was thrown horizontally only)

Acceleration acting horizontally, a_x = 0 m/s²  [ Since no acceleration acts horizontally) ]

Vertical Acceleration, a_y = 9.8 m/s² (Since only gravity acts on it)

Let 't' be the time taken to reach ground

Therefore, using equations of motion, we have

H= v_{oy}t+\frac{1}{2}a_yt^2

5= (0)t+\frac{1}{2}(9.8)t^2

t= \frac{10}{9.8}=1.02 s

Then using Equations of motion for horizontal motion,

R= v_{ox}t+\frac{1}{2}a_xt^2

20= v_{ox}(1.02)+\frac{1}{2}(0)(1.02)^2

v_{ox}= 19.6\ m/s

4 0
3 years ago
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