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Arturiano [62]
3 years ago
7

What can accurately be said about a resultant wave that displays both reinforcement and interference? A. The component waves hav

e different frequencies. B. Maximum interference occurs where the troughs of the two component waves are in phase. C. Molecules remain in their normal positions at spots of reinforcement. D. The crests of the two component waves are in phase where interference occurs in the resultant wave. Mark for review (Will be highlighted on the review page)
Physics
2 answers:
Agata [3.3K]3 years ago
7 0
<h3><u>Answer;</u></h3>

A. The component waves have different frequencies.

<h3><u>Explanation;</u></h3>
  • <em><u>interference is one of the property of waves that occurs when  two waves superpose to form a resultant wave of greater, lower, or the same amplitude.</u></em>
  • Interference occurs when two waves travelling in the same medium at the same time. It may be either a constructive or a destructive interference.
  • <em><u>Constructive interference occurs when the two waves are in phase and have the same frequency, the amplitudes are therefore, reinforced resulting to a constructive interference.</u></em> However, if the two waves are out phase the result will be a destructive interference.
Tanya [424]3 years ago
4 0
The answer is A. <span>The component waves have different frequencies.
The magnitudes of reinforcement usually really dependent on the number of frequencies and interference is usually caused due to the difference in frequencies. So, we can conclude that if the frequencies are different and causing interference, the reinforcement will also different
</span>
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Where is the near point of an normal eye when accidentally wear a contact lens with a power of +2.0 diopters?
Lerok [7]

Answer:

The near point of an eye with power of +2 dopters, u' = - 50 cm

Given:

Power of a contact lens, P = +2.0 diopters

Solution:

To calculate the near point, we need to find the focal length of the lens which is given by:

Power, P = \frac{1}{f}

where

f = focal length

Thus

f = \frac{1}{P}

f = \frac{1}{2} = + 0.5 m

The near point of the eye is the point distant such that the image formed at this point can be seen clearly by the eye.

Now, by using lens maker formula:

\frac{1}{f} = \frac{1}{u} + \frac{1}{u'}

where

u = object distance = 25 cm = 0.25 m = near point of a normal eye

u' = image distance

Now,

\frac{1}{u'} = \frac{1}{f} - \frac{1}{u}

\frac{1}{u'} = \frac{1}{0.5} - \frac{1}{0.25}

\frac{1}{u'} = \frac{1}{f} - \frac{1}{u}

Solving the above eqn, we get:

u' = - 0.5 m = - 50 cm

7 0
3 years ago
What happens to light when it changes speed?
Brut [27]
Hey there!

When light changes speed, it REFRACTS.
Your answer is going to be option C.

Hope this helps you.
Have a great day!
5 0
3 years ago
The gas pressure inside a container decreases when
avanturin [10]

Answer:

When the volume increases or when the temperature decreases

Explanation:

The ideal gas equation states that:

pV= nRT

where

p is the gas pressure

V is the volume

n is the number of moles of gas

R is the gas constant

T is the gas temperature

Assuming that we have a fixed amount of gas, so n is constant, we can rewrite the equation as

\frac{pV}{T}=const.

which means the following:

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8 0
3 years ago
A tow truck exerts a net horizontal force of 1050 N on a 760-kg car. What is the acceleration of the car during this time?
vovikov84 [41]
We can solve the problem by using Newton's second law of motion:
F=ma
where
F is the net force applied to the object
m is the object's mass
a is the acceleration of the object

In this problem, the force applied to the car is F=1050 N, while the mass of the car is m=760 kg. Therefore, we can rearrange the equation and put these numbers in, in order to find the acceleration of the car:
a= \frac{F}{m}= \frac{1050 N}{760 kg}=1.4 m/s^2

The equation also tells us that the acceleration and the force have same directions: therefore, since the force exerted on the car is horizontal, the correct answer is
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5 0
3 years ago
Does the same battery always deliver the same amount of flow to any circuit? Mention two observations of any circuits in this la
V125BC [204]

Answer:

Yes

Explanation:

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Hence the same amount of charge flow is delivered to any circuit.

attached below are examples

6 0
3 years ago
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