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Arturiano [62]
3 years ago
7

What can accurately be said about a resultant wave that displays both reinforcement and interference? A. The component waves hav

e different frequencies. B. Maximum interference occurs where the troughs of the two component waves are in phase. C. Molecules remain in their normal positions at spots of reinforcement. D. The crests of the two component waves are in phase where interference occurs in the resultant wave. Mark for review (Will be highlighted on the review page)
Physics
2 answers:
Agata [3.3K]3 years ago
7 0
<h3><u>Answer;</u></h3>

A. The component waves have different frequencies.

<h3><u>Explanation;</u></h3>
  • <em><u>interference is one of the property of waves that occurs when  two waves superpose to form a resultant wave of greater, lower, or the same amplitude.</u></em>
  • Interference occurs when two waves travelling in the same medium at the same time. It may be either a constructive or a destructive interference.
  • <em><u>Constructive interference occurs when the two waves are in phase and have the same frequency, the amplitudes are therefore, reinforced resulting to a constructive interference.</u></em> However, if the two waves are out phase the result will be a destructive interference.
Tanya [424]3 years ago
4 0
The answer is A. <span>The component waves have different frequencies.
The magnitudes of reinforcement usually really dependent on the number of frequencies and interference is usually caused due to the difference in frequencies. So, we can conclude that if the frequencies are different and causing interference, the reinforcement will also different
</span>
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If you lose control of your vehicle and collide with a fixed object, such as a tree, at 60 m.p.h., the force of impact is the sa
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You can compare the velocity of the car, 60 mph, with the velocity that a mass would acquire when falls from certain height.

First, convert 60 mph to m/s:

60 miles/h * 1.60 km/mile * 1000 m/km * 1h/3600s = 26.67 m/s

Second, calculate from what height a body in free fall reachs 26.67 m/s velocity when hits the floor.

free fall => Vf^2 = 2g*H => H = Vf^2 / (2g)

H = (26.67m/s)^2 / (2*9.8 m/s) = 36.2 m

If you consider that the height between the floors of a building is approximately 3.6 m, you get 36.2 m / 3.6 m/floor = 10 floors.

Then, you conclude that the force of impact is the same as driving you vehicle off a 10 story building.
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3 years ago
B. If you ranked yourself from 6 – 10, describe why it is important to you to be respectful in sports and in other activities, a
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Answer:

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2 years ago
A hawk leaves its nest in Fort Worth and travels 3,000 meters east. After snacking on a tasty rodent the hawk flies another 1,50
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I think the logical question here is to either find the distance or the displacement. They differ in such a way that distance is a scalar quantity that does not focus on the direction. Displacement is a vector quantity that covers the distance from the starting point to end point. Because it travels only in one direction (to the east), in this condition, distance is equal to displacement.

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2 years ago
The space shuttle usually orbited Earth at altitudes of around 300.0 km. 1) Determine the time for one orbit of the shuttle abou
777dan777 [17]

Answer:

Explanation:

distance of shuttle from centre of the earth = radius of the orbit

= 6300 + 300 = 6600 km

= 6600 x 10³

Formula of time period of the satellite

T = 2π R /v₀ , v₀ is orbital velocity

v₀ = √gR , ( if height  is small with respect to radius )

T = 2π R /√gR

= 2π√ R /√g

= 2 x 3.14 x √ 6600 x 10³ / √9.8

= 2 x 3.14 x 256.9 x 10 / 3.13

= 5154.41 s

= 5154.41 / 60 minutes

= 85.91 m

85.9 minutes.

2 ) No of sunrise per day = no of rotation per day

= 24 x 60 / 85.9

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3 0
3 years ago
The work done by an external force to move a -6.70 μc charge from point a to point b is 1.20×10−3 j .
ASHA 777 [7]

Answer:

108.7 V

Explanation:

Two forces are acting on the particle:

- The external force, whose work is W=1.20 \cdot 10^{-3}J

- The force of the electric field, whose work is equal to the change in electric potential energy of the charge: W_e=q\Delta V

where

q is the charge

\Delta V is the potential difference

The variation of kinetic energy of the charge is equal to the sum of the work done by the two forces:

K_f - K_i = W + W_e = W+q\Delta V

and since the charge starts from rest, K_i = 0, so the formula becomes

K_f = W+q\Delta V

In this problem, we have

W=1.20 \cdot 10^{-3}J is the work done by the external force

q=-6.70 \mu C=-6.7\cdot 10^{-6}C is the charge

K_f = 4.72\cdot 10^{-4}J is the final kinetic energy

Solving the formula for \Delta V, we find

\Delta V=\frac{K_f-W}{q}=\frac{4.72\cdot 10^{-4}J-1.2\cdot 10^{-3} J}{-6.7\cdot 10^{-6}C}=108.7 V

4 0
2 years ago
Read 2 more answers
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