Since we know that..
I = F . ∆t
= m . a . ∆t ( the puck accelerating after the collision with the hockey sticks)
= m . ∆v/∆t . ∆t
= m . ∆v
Solve for m, we get..
m = I / ∆v
= 4 / 12
= 1 / 3 kg or 0.33 kg
The object which is projected upwards. The kinetic energy imparted as its launch is converted into potential energy as an object Rises until, at the peak of its motion, all the kinetic energy has been converted to additional potential energy
Answer:
F = -319.2 N
Explanation:
Given that,
The mass of a bicyclist, m = 70 kg
Mass of the bicycle = 9.8 kg
The speed of a bicycle, v = 16 m/s
We need to find the magnitude of the braking force of the bicycle come to rest in 4.0 m.
The braking force is given by :
So, the required force is 319.2 N.
Risks are only in a persons
Answer:
1.065 km
Explanation:
The horizontal and vertical component of the canon ball when it's fired is
If we ignore air resistance, then gravitational acceleration g = -9.8m/s2 is the only thing that affects the vertical motion of the cannon ball. We can use the following equation to calculate the time it stays on air after it traveling h = -3.5m (down below the firing point) vertically
t = -0.07 or t = 9.64
Since t can only be positive we will pick t = 9.64
This is also the time it takes for the cannon ball to travel horizontally at the rate of 110.46 m/s
or 1.065 km