Answer:
Heat of vaporization will be 22.59 j
Explanation:
We have given mass m = 10 gram
And heat of vaporization L = 2.259 J/gram
We have to find the heat required to vaporize 10 gram mass
We know that heat of vaporization is given by
, here m is mass and L is latent heat of vaporization.
So heat of vaporization Q will be = 10×2.259 = 22.59 J
<span>the one that should be taken as consideration when describing the quality of a sound is: D.The number of the overtones in the sound
Too many overtones indicated that there is too many unrelated sound that make a lot of the sound's part became redundant and unecessary</span>
Momentum of the wagon increases by (200 x 3)
= 600 newton-sec
= 600 kg-m/sec
Answer:
4.14 cm.
Explanation:
Given,
For Coil 1
radius of coil, r₁ = 5.6 cm
Magnetic field, B₁ = 0.24 T
For Coil 2
radius of coil, r₂ = ?
Magnetic field, B₂ = 0.44 T
Using formula of maximum torque

Since both the coil experience same maximum torques
now,





Radius of the coil 2 is equal to 4.14 cm.
Answer:
the answer is b.
The team of scientist will make sure the products are edible