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3 years ago

The y-intercept is the point where the graph crosses the __ axis

Mathematics

1 answer:

Ede4ka [16]3 years ago

3 0

Answer:

what are the Options?

Step-by-step explanation:

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4a – 16 = a - 15 how do I solve

miv72 [106K]

Answer:

a = $\frac{1}{3}$

Step-by-step explanation:

4a -16 = a - 15

both left and right -a

then

4a - 16 -a = a - 15 -a

then

4a -a -16 = a -a -15

then

3a -16 = -15

both left and right + 16

then

3a -16 + 16 = -15 + 16

then

3a = 1

both left and right ÷3

then

3a ÷ 3 =1 ÷ 3

then

a = $\frac{1}{3}$

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4 years ago

If A is directly proportional to B and A = 1 13 when

Zielflug [23.3K]

Answer:

Step-by-step explanation:

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3 years ago

In the expression 4(3x+7), 3 is coefficient true or false?

GenaCL600 [577]

False. The 4 needs to be distributed to the terms in the parentheses, so the coefficient of x is 12.

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3 years ago

If x = 4 tan(θ), find sec(θ) in terms of x

prisoha [69]

Answer:

$\sec \theta = \pm \frac{ \sqrt{ {x}^{2} + 16} }{4}$

Step-by-step explanation:

$\because \: x = 4 \tan \theta \\ \therefore\frac{x}{4} = \tan \theta....(1) \\ \\ \because \: { \sec}^{2} \theta = 1 + { \tan}^{2} \theta \\ \therefore \: \sec \theta = \pm\sqrt{1 + { \tan}^{2} \theta } \\ \therefore \: \sec \theta = \pm\sqrt{1 + { \bigg( \frac{x}{4} \bigg)}^{2} } \\ \therefore \: \sec \theta = \pm\sqrt{1 + { \frac{x^{2}}{16} } } \\ \therefore \: \sec \theta = \pm\sqrt{{ \frac{16 + x^{2}}{16} } } \\ \therefore \: \sec \theta = \pm \frac{ \sqrt{ {x}^{2} + 16} }{4}$

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3 years ago

Help i-Ready math. No links and no guesses

RoseWind [281]

Answer:

648

Step-by-step explanation:

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3 years ago

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