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Furkat [3]
3 years ago
15

Fill in the blank to make the two fractions

Mathematics
2 answers:
Hunter-Best [27]3 years ago
4 0

Answer:

18

Step-by-step explanation:

3/4

24 ÷ 4 = 6

Multiply the top and bottom by 6

3/4 * 6/6 = 18/24

AURORKA [14]3 years ago
4 0

Answer:

18

Step-by-step explanation:

\frac{3}{4}  \frac{ \times 6}{ \times 6}  =  \frac{18}{24}

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A trinidadian who is planning to visit Canada changed $3192 to canadian currency. How many $ did the triodion received
DanielleElmas [232]

Answer:

$3934

Step-by-step explanation:

We know that the currency of different countries are different.

So, one US dollar = 1.23 Canadian dollar

Given : $3192

A trinidadian changed some US dollar to Canadian dollar who plans to visit Canada.

He exchanged $3192.

Therefore,

1 US dollar = 1.23 Canadian dollar

The value of $ 3192 will be equal to = 1.23 x 3192

                                                            = $ 3933.96

                                                            ≈ $ 3934

Therefore,  triodion received =  $ 3934.

8 0
3 years ago
Solve for x.........
vlabodo [156]

Answer:

x = 1 1/5

Step-by-step explanation:

1/3x = 2/5

multiply both sides by 3/1

x = 1 1/5

Hope this helps!!!

3 0
3 years ago
A 37 inch tv sells for $400. This is a $45 less than five times the cost of a 19 inch tv. Find the cost of the 19 inch tv.
adell [148]

Answer:

A 19 inch tv cost $89

Step-by-step explanation:

37 inch tv : 400 = 5x - 45

19 inch tv : x

We have the equation:

5x - 45 = 400

5x = 445

x = 89

4 0
3 years ago
Find parametric equations for the tangent line to the curve with the given parametric equations at the specified point. x = e−5t
Elan Coil [88]

Answer:

x = 1 - 5t

y = t

z = 1 - 5t

Step-by-step explanation:

For the equation of a line, we need a point and a direction vector. We are given a point (1, 0, 1).

Since the line is suppose to be a tangent to the given curve at the point (1, 0, 1), we need to find a tangent vector for which the curve passes through that point.

We have x = e^(-5t)cos5t

at t = 1, x = e^(-5)cos5

at t = 0, x = 1

y = e^(-5t)sin5t

at t = 1, y = e^(-5)sin5

at t = 0, y = 0

z = e^(-5t)

at t = 1, z = e^(-5)

at t = 0, z = 1

Clearly, the only parameter value for which the curve passes through the point (1, 0, 1) is t = 0.

In vector notation, the curve

r(t) = xi + yj + zk

= e^(-5t)cos5t i + e^(-5t)sin5t j + e^(-5t) k

r'(t) = [-5e^(-5t)cos5t - e^(-5t)sin5t] i +[e^(-5t)cos5t - 5e^(-5t)sin5t] j - 5e^(-5t) k

r'(0) = -5i + j - 5k

is a vector tangent at the point.

We get the parametric equation from this.

x = x(0) + tx'(0)

= 1 - 5t

y = y(0) + ty'(0)

= t

z = z(0) + tz'(0)

= 1 - 5t

8 0
3 years ago
Which is the best estimate for the width of your index finger
fgiga [73]
I'd say centimeters, if that's what you're looking for. Maybe 1-2 cm.
4 0
3 years ago
Read 2 more answers
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