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3 years ago

Find the measure of each angle indicated. Round to the nearest tenth.

Mathematics

2 answers:

vampirchik [111]3 years ago

6 0

Answer:

Step-by-step explanation:

eduard3 years ago

3 0

<h3>Answer: D) 55.7 degrees approximately</h3>

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The reference angle has AC = 12.3 as the opposite side and BC = 8.4 as the adjacent side. The tangent ratio ties the opposite and adjacent sides together.

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tan(angle) = opposite/adjacent

tan(theta) = AC/BC

tan(theta) = 12.3/8.4

theta = arctan(12.3/8.4)

theta = 55.6697828044967

theta = 55.7 degrees approximately

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arctan is the same as inverse tangent which is written as $\tan^{-1}$

make sure your calculator is in degree mode

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A CD tower is shaped like a cylinder and holds CDs with a diameter of 4.75 inches. If the CD tower is 12 inches tall, what is it

Agata [3.3K]

The answer is 212.54in^3

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4 years ago

A small military base housing 1,000 troops, each of whom is susceptible to a certain virus infection. Assuming that during the c

slava [35]

Answer:

$I=\frac{1000}{exp^{0,806725*t-0.6906755}+1}$

Step-by-step explanation:

The rate of infection is jointly proportional to the number of infected troopers and the number of non-infected ones. It can be expressed as follows:

$\frac{dI}{dt}=a*I*(1000-I)$

Rearranging and integrating

$\frac{dI}{dt}=a*I*(1000-I)\\\\\frac{dI}{I*(1000-I)}=a*dt\\\\\int\frac{dI}{I*(1000-I)}=\int a*dt\\\\-\frac{ln(1000/I-1)}{1000}+C=a*t$

At the initial breakout (t=0) there was one trooper infected (I=1)

$-\frac{ln(1000/1-1)}{1000}+C=0\\\\-0,006906755+C=0\\\\C=0,006906755$

In two days (t=2) there were 5 troopers infected

$-\frac{ln(1000/5-1)}{1000}+0,006906755=a*2\\\\-0,005293305+0,006906755=2*a\\a = 0,00161345 / 2 = 0,000806725$

Rearranging, we can model the number of infected troops (I) as

$-\frac{ln(1000/I-1)}{1000}+0,006906755=0,000806725*t\\\\-\frac{ln(1000/I-1)}{1000}=0,000806725*t-0,006906755\\-ln(1000/I-1)=0,806725*t-0.6906755\\\\\frac{1000}{I}-1=exp^{0,806725*t-0.6906755} \\\\\frac{1000}{I}=exp^{0,806725*t-0.6906755}+1\\\\I=\frac{1000}{exp^{0,806725*t-0.6906755}+1}$

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3 years ago

Gavin rolls a fair dice 48 times.<br> How many times would Gavin expect to roll an even number?

pantera1 [17]

Answer: The number of times Gavin expect to roll an even number =24

Step-by-step explanation:

Given: Numbers of a fair dice = 1, 2, 3, 4, 5, 6

even numbers = 2, 4, 6

odd numbers = 1, 3, 5

Probability of getting an even number = $\dfrac{3}{6}=\dfrac12$

If Gavin rolls a fair dice 48 times.

Then, the number of times Gavin expect to roll an even number = $48\times\dfrac12=24$

Hence, the number of times Gavin expect to roll an even number =24

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2 years ago

Which of the following, if substituted for y, would make the following inequality a true statement? –14 < y – 12?

trasher [3.6K]

Any number that is larger than -2.
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3 0

3 years ago

1/3t + 3/4 = 2/4 -t solve

olga55 [171]

Okay so I am going to summarize the work out process because its a lot to

Here we go

1/3 (t) + 3/4 - 2/4 - t = ?

1/2 (simplify )

(1/3 (T)+3/4 - 1/2 - (t) = ?

t (2) / 2

1 - 2(t) / 2 = ?

3/4 (simplify this )

1/3(t)+ 3/4 - [1 - 2(t) / 2 = ?

1/3 (this is re last one you have to simplify)

L (Denominator): 3

R (Denominator): 4

L: [L.C.M] : 4

R: [L.C.M] : 3

Basically , we just switched the dominators around

So, Therefore The of t is -3/16

T = -3/16

4 0

3 years ago