Answer:
8/17
General Formulas and Concepts:
<u>Trigonometry</u>
- [Right Triangles Only] cos∅ = adjacent over hypotenuse
Step-by-step explanation:
<u>Step 1: Define</u>
We are given a right triangle. We can use trig to find the ratio.
<u>Step 2: Identify</u>
<em>POV from angle S</em>
Adjacent = 8
Hypotenuse = 17
<u>Step 3: Write</u>
- Substitute [cosine]: cos(s) = 8/17
5^(x+7)=(1/625)^(2x-13)
We move all terms to the left:
5^(x+7)-((1/625)^(2x-13))=0
Domain of the equation: 625)^(2x-13))!=0
x∈R
We add all the numbers together, and all the variables
5^(x+7)-((+1/625)^(2x-13))=0
We multiply all the terms by the denominator
(5^(x+7))*625)^(2x+1-13))-((=0
We add all the numbers together, and all the variables
(5^(x+7))*625)^(2x-12))-((=0
We add all the numbers together, and all the variables
(5^(x+7))*625)^(2x=0
not sure if this is right :/
1/3 is 1 and 1 is 2 and 3 is 4 and 9 is 10