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Anit [1.1K]
3 years ago
5

How do I solve this?

Mathematics
1 answer:
Vanyuwa [196]3 years ago
6 0
1/3 is 1 and 1 is 2 and 3 is 4 and 9 is 10
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The sum of twice a number and 5 is at most 3 less than the number
Rasek [7]

So this is our inequality in algebraic terms: 2n+5\leq n-3

Firstly, subtract n on both sides of the inequality: n+5\leq -3

Next, subtract 5 on both sides of the inequality, and <u>your inequality is n\leq -8</u>

4 0
4 years ago
The expression two square root of three minus square root of 27 is equivalent to
never [62]

Answer:

-0.954(rounded)

Step-by-step explanation:

first write it in number form

√2(3)-√27

the exact form will be 3√2-3√27 = -0.954(rounded)

5 0
3 years ago
Read 2 more answers
Millions of years ago, the Indian plate began pushing gradually towards the Eurasian plate. The land above started rising in var
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Folded mountain with waves, twists, and turns. I believe because the article stated it was gradual and various patterns were formed.
7 0
3 years ago
What is 76,808 rounded to the nearest 100?
Neporo4naja [7]

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76,800

Step-by-step explanation:

This is because 808 is closer to 800

5 0
3 years ago
Show all work to factor x^4 − 17x^2 + 16 completely.
Dmitrij [34]

Answer:

x^{4}-17x^{2} +16 = (x -1)(x + 1)(x - 4)(x + 4)

Step-by-step explanation:

At first, let us find the first two factors of x^{4}-17x^{2} +16

∵ The sign of the last term is positive

∴ The middle signs of the two factors are the same

∵ The sign of the middle term is negative

∴ The middle signs of the two factors are negative

∵ x^{4} = x² × x² ⇒ first terms of the two factors

∵ 16 = -1 × -16 ⇒ second terms of the two factors

∵ x²(-1) + x²(-16) = -x² + -16x² = -17x² ⇒ the value of the middle term

∴ (x² - 1) and (x² - 16) are the factors of x^{4}-17x^{2} +16

Now let us factorize each factor

→ The factors of the binomial a² - b² (difference of two squares) are

   (a - b) and (a + b)

∵ x² - 1 is the difference of two squares

∴ Its factors are (x - 1) and (x + 1)

∵ x² - 16 is the difference of two squares

∴ Its factors are (x - 4) and (x + 4)

∵ (x -1), (x + 1), (x - 4), and (x + 4) are the factors of (x² - 1) and (x² - 16)

∵ (x² - 1) and (x² - 16) are the factors of x^{4}-17x^{2} +16

∴ (x -1), (x + 1), (x - 4), and (x + 4) are the factors of x^{4}-17x^{2} +16

∴  x^{4}-17x^{2} +16 = (x -1)(x + 1)(x - 4)(x + 4)

8 0
3 years ago
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