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Viktor [21]
2 years ago
6

Is my student correct?​

Mathematics
2 answers:
tino4ka555 [31]2 years ago
8 0

Answer:

Yes

Step-by-step explanation:

There hasn't been a chemical change, rather, just a physical change. All that had happened was a liquid turning into a solid, which doesn't require a change in elements of the liquid itself.

Finger [1]2 years ago
7 0

Answer:

YES

Step-by-step explanation:

BECAUSE A CHEMICAL CHANGE STAYS THE SAME AND A PHYSICAL CHANGE CAN GO BACK TO NORMAL

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In a certain assembly plant, three machines B1, B2, and B3, make 30%, 20%, and 50%, respectively. It is known from past experien
diamong [38]

Answer:

The probability that a randomly selected non-defective product is produced by machine B1 is 11.38%.

Step-by-step explanation:

Using Bayes' Theorem

P(A|B) = \frac{P(B|A)P(A)}{P(B)} = \frac{P(B|A)P(A)}{P(B|A)P(A) + P(B|a)P(a)}

where

P(B|A) is probability of event B given event A

P(B|a) is probability of event B not given event A  

and P(A), P(B), and P(a) are the probabilities of events A,B, and event A not happening respectively.

For this problem,

Let P(B1) = Probability of machine B1 = 0.3

P(B2) = Probability of machine B2 = 0.2

P(B3) = Probability of machine B3 = 0.5

Let P(D) = Probability of a defective product

P(N) = Probability of a Non-defective product

P(D|B1) be probability of a defective product produced by machine 1 = 0.3 x 0.01 = 0.003

P(D|B2) be probability of a defective product produced by machine 2 = 0.2 x 0.03 = 0.006

P(D|B3) be probability of a defective product produced by machine 3 = 0.5 x 0.02 = 0.010

Likewise,

P(N|B1) be probability of a non-defective product produced by machine 1 = 1 - P(D|B1) = 1 - 0.003 = 0.997

P(N|B2) be probability of a non-defective product produced by machine 2  = 1 - P(D|B2) = 1 - 0.006 = 0.994

P(N|B3) be probability of a non-defective product produced by machine 3 = 1 - P(D|B3) = 1 - 0.010 = 0.990

For the probability of a finished product produced by machine B1 given it's non-defective; represented by P(B1|N)

P(B1|N) =\frac{P(N|B1)P(B1)}{P(N|B1)P(B1) + P(N|B2)P(B2) + (P(N|B3)P(B3)} = \frac{(0.297)(0.3)}{(0.297)(0.3) + (0.994)(0.2) + (0.990)(0.5)} = 0.1138

Hence the probability that a non-defective product is produced by machine B1 is 11.38%.

4 0
3 years ago
a tennis player hits a serve that cannot be returned 45 percent of the time. Out of 300 serves, how many can yiu predict will no
lubasha [3.4K]

Remember that 45%=45/100=0.45

So if the tennis player serves the ball 300 times, and 45% cannot be returned, then we can use the following expression to solve for the answer:

300*0.45=135serves

Answer: 135 serves will not be returned
4 0
3 years ago
Find range of the following function
Marina CMI [18]

Answer:

4x to the power of 2

Step-by-step explanation:

3 0
3 years ago
Find the area if the shaded segment. Round your answer to the nearest square foot.
8090 [49]
2 ft I think
Is the answer
5 0
2 years ago
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The length of a rectangle is given by L=3y + 4x while the width is
Wittaler [7]

Answer:

21y² +34 yx + 8x²

Step-by-step explanation:

Area of a rectangle is given by L×W where L is length, and W is width

Given L=3y+4x

          W=7y+2x

Area= (3y+4x) × (7y+2x)

          3y(7y+2x) + 4x(7y+2x)

           21y² + 6yx +28yx+8x²

            21y² +34 yx + 8x²

3 0
2 years ago
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