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GaryK [48]
3 years ago
6

True or False? 2 is a solution to 8m - 6 < 10 True False

Mathematics
2 answers:
Murljashka [212]3 years ago
7 0

Answer:

False

Step-by-step explanation:

8m - 6 < 10

Add 6 to each side

8m -6+6 < 10+6

8m < 16

Divide by 8

8m/8 <16/8

m < 2

m must be less than 2

2 is not a solution

mina [271]3 years ago
6 0

Answer:

TRUE

Step-by-step explanation:

You might be interested in
Question 2 (2 points)
hoa [83]

Answer:

4) The limit does not exist.

General Formulas and Concepts:

<u>Calculus</u>

Limits

  • Right-Side Limit:                                                                                             \displaystyle \lim_{x \to c^+} f(x)
  • Left-Side Limit:                                                                                               \displaystyle \lim_{x \to c^-} f(x)

Limit Rule [Variable Direct Substitution]:                                                             \displaystyle \lim_{x \to c} x = c

Step-by-step explanation:

*Note:

For a limit to exist, the right-side and left-side limits must be equal to each other.

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle f(x) = \left\{\begin{array}{ccc}5 - x ,\ x < 5\\8 ,\ x = 5\\x + 3 ,\ x > 5\end{array}

<u>Step 2: Find Left-Side Limit</u>

  1. Substitute in function [Left-Side Limit]:                                                       \displaystyle \lim_{x \to 5^-} 5 - x
  2. Evaluate limit [Limit Rule - Variable Direct Substitution]:                          \displaystyle \lim_{x \to 5^-} 5 - x = 5- 5 = 0

<u>Step 2: Find Left-Side Limit</u>

  1. Substitute in function [Right-Side Limit]:                                                     \displaystyle \lim_{x \to 5^+} x + 3
  2. Evaluate limit [Limit Rule - Variable Direct Substitution]:                           \displaystyle \lim_{x \to 5^+} x + 3 = 5 + 3 = 8

∴ since  \displaystyle \lim_{x \to c^+} f(x) \neq \lim_{x \to c^-} f(x)  ,  \displaystyle  \lim_{x \to 5} f(x) = \text{DNE}

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

5 0
3 years ago
If a and b can be replaced with any whole number in the equation a+ b=19. then there is?
Schach [20]

Answer:

C

Step-by-step explanation:

There isnt infinite because there is an answer of 19, and only so many whole numbers can add up to 19

There isnt 1 because 11+8 and 5+14 both equal 19

4 0
3 years ago
Rename 4thousand7hundred
Andreas93 [3]
4,700 is one of the correct answers to this question.
3 0
3 years ago
I don't understand all three. What am I supposed to do and what is the answer?
AlladinOne [14]

Answer:

Step-by-step explanation:

The Domain means all possible values that x can be.

The range is the outcomes you get when you plug in the domain.

For each function, choose values for x.

Then solve

The outcome you get is f(x)

F(X) is an easier way of saying y,

If its easier this way, in terms of y, the equations would be y=-4x, y=x+6, and y=3x+2. You would solve these as you solve linear equations!

Ordered pair of [x,f(x)]

Lets Start!

#1

x | -4x | f(x)  

Lets use the values -2, -1, 0, 1, and 2 for x.

-2 | -4(-2) | 8  (-2,8)

-1 | -4(-1) | 4  (-1,4)

0 | -4(0) | 0  (0,0)

1 | -4(1) | -4  (1,-4)

2 | -4(2) | -8  (2,-8)

Domain we have right now- {-2,-1,0,1,2}

Range we have right now- {8,4,0,-4,-8}

Domain and Range of entire function- All real numbers

#2

x | x+6 | f(x)

Lets use the values -2, -1, 0, 1, and 2 for x.

-2 | -2 + 6 | 4

-1 | -1 + 6 | 5

0 | 0 + 6 | 6

1 | 1 + 6 | 7

2 | 2 + 6 | 8

Domain we have right now- {-2,-1,0,1,2}

Range we have right now- {4,5,6,7,8}

Domain and Range of entire function- All real numbers

#3

x | 3x + 2 | f(x)

-2 | 3(-2) + 2 | 4

-1 | 3(-1) + 2 | -1

0 | 3(0) + 2 | 2

1 | 3(1) + 2 | 5

2 | 3(2) + 2 | 8

Domain we have right now- {-2,-1,0,1,2}

Range we have right now- {4,-1,2,5,8}

Domain and Range of entire function- All real numbers

Hope i helped, Brainliest would be appreciated.

Have a nice day!

   -Aadi x

3 0
3 years ago
W-6.67=2.27<br><br> I need help with this
kirza4 [7]
W is equal to 8.94 !!
4 0
3 years ago
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