Question

What is the value of the following expression? 2×{6+ [12÷(3+1)]} - 1

Answer 1

Answer:

17

Step-by-step explanation:

To solve the expression, we have to operate using a specific order.

First, we need to eliminate parenthesis, second brackets and third braces. That's the right order. Another important thing is that the right order to operate is first multiplication and division, and at the end add and subtracting, this operation order has the most importance where we don't have grouping signs.

$2\times \{6+ [12\div(3+1)]\} - 1\\2\times \{6+ [12\div4]\} - 1\\2\times \{6+ 3\} - 1\\2\times 9 - 1\\18-1\\17$

Therefore, the value of the expression is 17.

Answer 2

First you start with the inner most parenthesis , 3+1 = 4, Then you do 12 / 4 = 3
now you're left with 3 - 1, You can finish that I hope