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notsponge [240]
3 years ago
8

Points P, Q, and R are shown on the number line. What is the distance between point P and point Q? P(-76) Q(-24) R(0) A) 52 unit

s B) 63 units C) 70 units D) 100 units
Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
4 0

Answer:

A) 52 units

Step-by-step explanation:

The length of a line joining 2 points on a number line is given by the difference between the co-ordinates of the 2 points.

Therefore PQ= \left ( Q \right )-\left ( P \right )= \left ( -24 \right )-\left ( -76 \right )= 52

Hence the length of the line is 52 units

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Find k so that the distance from (–1, 1) to (2, k) is 5 units.
velikii [3]

Answer:

k = -3 or 5

Step-by-step explanation:

The given parameters are;

The line extends from points (-1, 1) to point (2, k)

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The formula for the length, l, of a line given its coordinates can be  found by the following formula;

l = \sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

Therefore, we have;

5 = \sqrt{\left (k-1 \right )^{2}+\left (2-(-1)  \right )^{2}}

Which, by squaring both sides, gives;

25 = (k - 1)² + (2 - (-1))² = (k - 1)² + (2 + 1)² = (k - 1)² + 3²

25 = (k - 1)² + 3² = k² - 2·k + 1 + 9

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0 = k² - 2·k - 15

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Therefore, k = -3 or 5

When k - -3, we have;

\sqrt{\left ((-3)-1 \right )^{2}+\left (2-(-1)  \right )^{2}}= \sqrt{(-4)^2+3^2} = \sqrt{16 + 9}  = \sqrt{25} = 5

When k = 5, we have;

\sqrt{\left (5-1 \right )^{2}+\left (2-(-1)  \right )^{2}}= \sqrt{4^2+3^2} = 5

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