The perimeter of △CDE is 55 cm. A rhombus DMFN is inscribed in this triangle so that vertices M, F, and N lie on the sides CD ,
2 answers:
Answer:
CD=20 cm and DE=15 cm. CD=20 cm and DE=15 cm.
Step-by-step explanation:
A rhombus DMFN is inscribed in such a way that it is inscribed in triangle CDE with the vertices M, F, and N l on the sides CD , CE , and DE respectively.
Now, in rhombus, the parallel sides are always parallel, therefore
MF║DE, thus, by the basic proportionality condition.
It is given that CF=8 cm and EF=12 cm, therefore, .
That is CM=8 cm and MD=12 cm. Therefore, CD=CM+MD=8+12=20.
According to question, Perimeter of △CDE =55 cm
⇒CD+DE+CE=55
⇒20+DE+20=55
⇒DE=15 cm
Hence, CD=20 cm and DE=15 cm.
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Answer:
The new ramp must be 54 inches long than the old ramp to meet the requirement of the new law
Step-by-step explanation:
Old height to length ratio is:
h : l = 2 : 15.
Height of old ramp h = 12
Length of old ramp can be find out by putting h = 12 in the above ratio
Length of old ramp = 90
Height to length ratio by current law:
h : l = 1 : 12
Height will be the same i.e. h = 12
Length of new ramp = 144
How much longer the new ramp should be to meet the new ratio law:
New length - Old length = 144 - 90 = 54 inches