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slavikrds [6]
4 years ago
11

The perimeter of △CDE is 55 cm. A rhombus DMFN is inscribed in this triangle so that vertices M, F, and N lie on the sides CD ,

CE , and DE respectively. Find CD and DE if CF=8 cm and EF=12 cm.
Mathematics
2 answers:
tamaranim1 [39]4 years ago
8 0

Answer:

CD=20 cm and DE=15 cm. CD=20 cm and DE=15 cm.

Step-by-step explanation:

A rhombus DMFN is inscribed in such a way that it is inscribed in  triangle CDE with the vertices M, F, and N l on the sides CD , CE , and DE respectively.

Now, in rhombus, the parallel sides are always parallel, therefore

MF║DE, thus, \frac{CM}{MD}=\frac{CF}{EF} by the basic proportionality condition.

It is given that CF=8 cm and EF=12 cm, therefore, \frac{CM}{MD}=\frac{8}{12}.

That is CM=8 cm and MD=12 cm. Therefore, CD=CM+MD=8+12=20.

According to question, Perimeter of △CDE =55 cm

⇒CD+DE+CE=55

⇒20+DE+20=55

⇒DE=15 cm

Hence, CD=20 cm and DE=15 cm.

Dafna1 [17]4 years ago
8 0

Answer:

CD=14

DE=21

Step-by-step explanation:

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Step-by-step explanation:

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4 0
3 years ago
-3/5x - 7/20x + 1/4x= -56
romanna [79]

Answer:

x = 80

Step-by-step explanation:

Combine − 3/5x and 7/20x to get -19/20x.

Then combine -19/20x and 1/4x and you get -7/10x.

Then you multiply both sides by -10/7 which is the reciprocal of -7/10.

Make -56(-10) one fraction.

Multiply -56 and -10 and you get 560.

Then divide 560 by 7 to get 80.

 

​  

8 0
3 years ago
Read 2 more answers
Find the circumference of a circle whose area is 24
zalisa [80]

The answer is: " 17.35 " .

__________________________________

→ The circumference of the circle is: " 17.35 units " .

__________________________________


The area, "A", of a circle:

A = \pi * r² ;

Note: \pi  = 3.14 .

The area of the circumference, "C", of a circle:

C = 2 \pi r .

__________________________________________

Given:

A = 24 ;

Use the formula for the area, "A" of a circle, to find the radius, "r" .

Then, plug the value obtained for "r" into the formula for the circumference, "C" , of a circle:

C = 2\pi r l

To solve for the circumference, "C", of the circle.

________________

A = \pi  *  r^{2} ;

24 = 3.14 * r² ;

↔ 3.14 * r² = 24 ;

Divide each side of the equation by "(3.14)" ;

[3.14 * r²] / 3.14 = (24) / (3.14) ;

to get:

→ r² = 7.64331210191 ;

Take the positive square root of each side of the equation;

to isolate "r" on one side of the equation; & to solve for the radius, "r" ;

→ ⁺√(r²) = ⁺√(7.64331210191) ;

to get:

→ r = 2.76281034802 ;

____________________________

Now, plug this "obtained value" for the radius, "r" into the equation for the formula for the circumference, "C" of a circle:

→ C = 2 \pi * r ;

to solve for the circumference, "C", of the circle:

→ C = 2 * (3.14) * (2.76281034802) ;

= (6.28) * (2.76281034802) ;

= 17.3504489856 ;

→ round to: " 17.35 units" .

__________________________________

The answer is: " 17.35 " .

__________________________________

→ The circumference of the circle is: " 17.35 units " .

__________________________________

6 0
3 years ago
-52 times the difference between a number and 14 is equal to the number plus 3
xenn [34]
X=number looked for
we have this equation:
-52(x-14)=x+3
we solve this equation:
-52x+728=x+3
-52x-x=3-728
-53x=-725
x=-725/-53=725/53 ≈13,68

Solution: 725/53

To check:
the difference between 725/53 and 14=725/53  - 14=(725-742)/53=-17/53
-52 times the diference is= -52(-17/53)=884/53
The number plus 3=725/53 + 3=(725+159)/53=884/53
3 0
3 years ago
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