Answer:
3 Cycles
Explanation:
Every cycle on a cosine function are marked by the completion of 5 key points when moving along the x-axis:
(5, 0, -5, 0, 5)
This cycle has a frequency of 2, occurring once every second, thus answering our question easily.
from,
d = 1/2gt² - eqn for free falling object
12 = 1/2 * 9.8 * t²
24 = 9.8*t²
t = 1.56 s.
It is important to look at all the information's that are given in the question very closely. Let us write them write first.
Radius of the spa = <span>5/√2-1 feet
Now
Perimeter of the circle = </span><span>2πr
= 2</span>π (5/√2-1)
= <span>π(5/(√2-1)*(√2+1)/(√2+1) </span>
<span> = 2π(5/(√2+1))/(2-1) </span>
<span> = 10π(√2+1)
I hope that the procedure is clear enough for you to understand.</span>
Answer:
Migration
Explanation:
Migration is the movement of organisms from one region or place of habitat to another region. Organisms migrate from one region to another to increase their rates of survival. Migration of organisms from one habitat to another may be due to unavailability of insufficiency of resources that are required for their survival.
I assume the 100 N force is a pulling force directed up the incline.
The net forces on the block acting parallel and perpendicular to the incline are
∑ F[para] = 100 N - F[friction] = 0
∑ F[perp] = F[normal] - mg cos(30°) = 0
The friction in this case is the maximum static friction - the block is held at rest by static friction, and a minimum 100 N force is required to get the block to start sliding up the incline.
Then
F[friction] = 100 N
F[normal] = mg cos(30°) = (10 kg) (9.8 m/s²) cos(30°) ≈ 84.9 N
If µ is the coefficient of static friction, then
F[friction] = µ F[normal]
⇒ µ = (100 N) / (84.9 N) ≈ 1.2