Which of the following best describes philosophy

Infrared light of wavelength 2.5 µm illuminates a 0.20-mm-diameter hole. What is the angle of the first dark fringe in radians?

stepan [7]

Answer:

Θ=0.01525 rad

or

Θ=0.87°

Explanation:

Given data

wavelength λ=2.5 µm =2.5×10⁻⁶m

Diameter d=0.20 mm =0.20×10⁻³m

To find

Angle Θ in radians and degree

Solution

Circular apertures have first dark fringe at

Θ=(1.22λ)/d

Substitute the given values

So

Θ=[1.22(2.5×10⁻⁶m)]/0.20×10⁻³m

Θ=0.01525 rad

or

Θ=0.87°

6 0

3 years ago

An object accelerates from rest at a constant rate covering a distance of 18 meters in 3 seconds. What is its rate of accelerati

ozzi

Answer:

4

18*2=36
36/(3*3)=4

4 0

3 years ago

Read 2 more answers

In this problem, you will practice applying this formula to several situations involving angular acceleration. in all of these s

MatroZZZ [7]

<span>A- 2*[(m1 - m2)/(m1 + m2)]*g/L The rotation is in the counterclockwise direction and the angular acceleration is positive. B- 2*[(m1 - m2)/(m1+ m2 +mbar/3)]*g/L The rotation is in the counterclockwise direction and the angular acceleration is positive.</span>

6 0

3 years ago

The intensity of sunlight at the Earth is about 1367 W/m^2. How many times further away would the Sun have to be from the Earth

grandymaker [24]

The intensity of sunlight on the Earth is about 1367 W/m^2. The earth has to be 131 the distance farther away

This is further explained below.

<h3>What is the distance?</h3>

Generally, bet the power emitted by the sun is P. so. at the distance of earth intensely where $r_E$ is the distance of the earth from the sun. were $I_1=1362 \frac{w}{m^2}$

Therefore

p=4 $\pi 1367 r_E^2$

let at distance $\gamma r_E$$ is a positive number) the intensity is the same as the intensity at 10m away from a 100w bulb. So.

In conclusion,

$\begin{aligned}&\frac{P}{4 \pi\left(\gamma r_{\varepsilon}\right)^2}=\frac{100}{4 \pi 10^2}\\\\&\text { or, }\left(\gamma r_E\right)^2=P=4 \pi 1367 r_E^2\\\\&\therefore \gamma=\sqrt{4 \pi \times 1367}\\\\&=131.06\\\\ }\end{aligned}$

Read more about distance

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7 0

1 year ago

If a light is moved twice (2x) as far from a surface, the area the light covers is ___ as big.

Serga [27]

Answer:

The correct option is;

- 4x

Explanation:

From the inverse square law, as the distance from the source of a physical quantity increases, the intensity of the source is spread over an area proportional to the square of the distance of the object from the source

The inverse square law can be presented as follows;

$I = \dfrac{S}{4\times \pi \times r^2 }$

As the distance, r, increases, the surface it covers also increases by the power of 2

Therefore, where the distance increases from r to 2·r, we have;

When, I, remain constant

$I = \dfrac{4\times S}{4\times \pi \times (2\cdot r)^2 } = I = \dfrac{4\times S}{4\times 4\times \pi \times r^2 } = \dfrac{S}{4\times \pi \times r^2 }$

The surface increases to 4·S by the inverse square law

Therefore, the correct option is 4 × x.

3 0

3 years ago