Ask question

Ask question

All categories

4 years ago

9

Which of the following is an example of biological weathering

1 answer:

7nadin3 [17]4 years ago

3 0

An example of biological weathering is the widening of gaps in rocks caused by tree roots since pressure or stress is exerted on the rocks due to the growing plant roots. The pressure is exerted by a biological process (i.e., growing roots), even though the process is physical.

Plants and animals and its action speeds up mechanical and or chemical weathering, which in turn causes biological weathering.

<span>With the help of the chemicals that are produced by the tiniest bacteria, algae and liches, the rocks which they live in are also broken down by them in order to get the nutrients they need.</span>

You might be interested in

An object of mass 4kg is moving along a horizontal plane. If the coefficient of kinetic friction is 0.2 find the friction force

lana66690 [7]

Answer:

The friction force acting on the object is 7.84 N

Explanation:

Given;

mass of object, m = 4 kg

coefficient of kinetic friction, μk = 0.2

The friction force acting on the object is calculated as;

F = μkN

F = μkmg

where;

F is the frictional force

m is the mass of the object

g is the acceleration due to gravity

F = 0.2 x 4 x 9.8

F = 7.84 N

Therefore, the friction force acting on the object is 7.84 N

5 0

4 years ago

5. The equation shows the formation of nitrogen and hydrogen. What effect does increasing the pressure have on this equilibrium?

bezimeni [28]

more hydrogen and nitrogen form

Hope this helps :)

6 0

3 years ago

A boulder resting on a high cliff has _____ energy.

Juliette [100K]

The answer to that question is Potential Energy. Plz give me Brainliest

7 0

3 years ago

Read 2 more answers

A potter's wheel is rotating around a vertical axis through its center at a frequency of 2.0 rev/s. The wheel can be considered

mart [117]

Answer:

$\omega_f=12.2954 \,rad.s^{-1}$ i.e.

$Frequency=1.9569\,rev.s^{-1}$

Explanation:

Given:

angular speed, $\omega_i =2\times 2\pi \,rad.s^{-1}$

mass of the disk, $M=4.9\,kg$

radius of the disk, $R=0.2\,m$

mass of the chunk, $m=2.7\,kg$

radius of the chunk, $r=0.04\,m$

We know that the angular momentum is given by:

$L=I.\omega$

and moment of inertia for a disc:

$I=\frac{1}{2} m.r^2$

According to the conservation of angular momentum, the final angular momentum is equal to the initial angular momentum.

$\frac{1}{2} \times M.R^2\times \omega= \frac{1}{2} \times (M.R^2+m.r^2) \omega_f$

$4.9\times 0.2^2\times (2\times 2\pi)=(4.9\times 0.2^2+2.7\times 0.04^2 )\tiems \omega_f$

$\omega_f=12.2954 \,rad.s^{-1}$

$Frequency=1.9569\,rev.s^{-1}$

4 0

4 years ago

HELLLPPPPPP!!!!!!

Bond [772]

DIVIDE THEN MUTPLY THEN YOU AEMPLY SUCK

3 0

3 years ago