Question

While competing in the olympics, an athlete hurls a discus with a velocity of 14 m/s at an angle of 51. what is the horizontal component of the discus's velocity?

Answer 1

Answer:

Horizontal component of velocity is 8.81 m/s.

Explanation:

It is given that,

An athlete hurls a discus with a velocity of, v = 14 m/s  

Angle with the ground, θ = 51°

We have to find the horizontal component of discus's velocity. The horizontal component of velocity is given by :

$v_x=v\ cos\ \theta$

$v_x=14\ m/s\times \ cos(51)$

$v_x=8.81\ m/s$

Hence, the horizontal component of discus's velocity is 8.81 m/s.

Answer 2

Cos 51 = adjacent / hypotenuse