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Answer:
def analyze_text(sentence):
count = 0
e_count = 0
for s in sentence:
s = s.lower()
if s.isalpha():
count += 1
if s == "e":
e_count += 1
return "The text contains " + str(count) + " alphabetic characters, of which " + str(e_count) + " (" + str(e_count*100/count) + "%) are ‘e’."
Explanation:
Create a function called analyze_text takes a string, sentence
Initialize the count and e_count variables as 0
Create a for loop that iterates through the sentence
Inside the loop, convert all letters to lowercase using lower() function. Check each character. If a character is a letter, increment the count by 1. If a character is "e", increment the e_count by 1.
Return the count and e_count in required format
D. all of these, since it depends on how the cell is formatted.
A benefit, profit, or value of something that must be given up to acquire or achieve something else. Since every resource (land, money, time, etc.) can be put to alternative uses, every action, choice, or decision has an associated opportunity cost<span>.</span>
