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Lorico [155]
3 years ago
13

Yesterday stock in chambers translation sold for $87.19 per share. Today, the same share costs $95.45. How would the net change

appear in a stock listing?
A. 1.09
B. -1.09
C. 8.26
D.-8.26
Mathematics
2 answers:
Andrews [41]3 years ago
7 0
The net change that appears in a stock listing is the difference between the price of the stock at closing and the previous day's price. Therefore, the net change would be
$95.45 - $87.19 = $ 8.26
The answer is
<span>C. 8.26</span><span /><span>
</span>
erastovalidia [21]3 years ago
6 0

Answer:

The net change appear in a stock listing is  8.26.

Option (C) is correct .

Step-by-step explanation:

As given

Yesterday stock in chambers translation sold for $87.19 per share.

Today, the same share costs $95.45.

Thus

Net change in a stock = Today share cost - Yesterday share cost

Putting the value

Net change in a stock = $95.45 - $87.19

                                     = $ 8.26

Therefore the net change appear in a stock listing is  8.26.

Option (C) is correct .

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6,2,2/3,..<br> Find the 8th term
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Step-by-step explanation:

This is a geometric progression.

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Roll two fair dice. Each die has six faces. A. Let A be the event that either a 3 or 4 is rolled first followed by an odd number
zhenek [66]

Answer:

A. 0.16

B. 0.58

C. No

D. Dependent

Step-by-step explanation:

A.

The sampling space has 36 outcomes.

The event A has 6 outcomes (3,1), (3,3), (3,5), (4,1), (4,3),(4,5)

So P(A)= 6/36 = 0.16

B.

The table in the picture shows the 15 outcomes that are not allowed, so there are 36-15 = 21 possible outcomes for B and its probability is 21/36 = 0.58

C.

Are A and B mutually exclusive events?

No since their intersection is not empty, for example (3,1) belongs to both A and B

D.

In order for A and B to be independent, it must happen that

P(A∩B)=P(A)P(B)

A∩B={(3,1),(3,3),(4,1)} so P(A∩B) = 3/36  

whereas

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4 years ago
Point X is the incenter of ΔABC.
masha68 [24]

Answer:

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7 0
3 years ago
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How do you know what angle degree goes on each corner?
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Let'sSo, we gave 2 parallel lines and 2 transversals, we have to match the angles.

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Let's move on to angle e,

\begin{gathered} e=b\text{ (Vertically opposite angles)} \\ \text{but b = 115}^o \\ e=115^o^{} \end{gathered}

Let's move on to angle d,

d=110^o\text{ (V}ertically\text{ opposite angles)}

Moving to angle c, we have;

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