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4 years ago

F(x) equals 2X over the X axis what is the new function

Mathematics

1 answer:

tatyana61 [14]4 years ago

4 0

Answer:

f(x)= 2x + x

Step-by-step explanation:

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What’s the answer to this

creativ13 [48]

Answer: i d k

Step-by-step explanation:

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3 years ago

3.25- 13 tenths A:10.25 B:3.12 C:2.95

timofeeve [1]

Answer:

its B:3.12

Step-by-step explanation:

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3 years ago

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A sample of 30 11th graders were asked to select a favorite pattern out of six choices. The following display shows what their f

skelet666 [1.2K]

false-apex

but each question seems to be different so some people could have true but mine was false

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3 years ago

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If S_1=1,S_2=8 and S_n=S_n-1+2S_n-2 whenever n≥2. Show that S_n=3⋅2n−1+2(−1)n for all n≥1.

Snezhnost [94]

You can try to show this by induction:

• According to the given closed form, we have $S_1=3\times2^{1-1}+2(-1)^1=3-2=1$ , which agrees with the initial value S₁ = 1.

• Assume the closed form is correct for all n up to n = k. In particular, we assume

$S_{k-1}=3\times2^{(k-1)-1}+2(-1)^{k-1}=3\times2^{k-2}+2(-1)^{k-1}$

and

$S_k=3\times2^{k-1}+2(-1)^k$

We want to then use this assumption to show the closed form is correct for n = k + 1, or

$S_{k+1}=3\times2^{(k+1)-1}+2(-1)^{k+1}=3\times2^k+2(-1)^{k+1}$

From the given recurrence, we know

$S_{k+1}=S_k+2S_{k-1}$

so that

$S_{k+1}=3\times2^{k-1}+2(-1)^k + 2\left(3\times2^{k-2}+2(-1)^{k-1}\right)$

$S_{k+1}=3\times2^{k-1}+2(-1)^k + 3\times2^{k-1}+4(-1)^{k-1}$

$S_{k+1}=2\times3\times2^{k-1}+(-1)^k\left(2+4(-1)^{-1}\right)$

$S_{k+1}=3\times2^k-2(-1)^k$

$S_{k+1}=3\times2^k+2(-1)(-1)^k$

$\boxed{S_{k+1}=3\times2^k+2(-1)^{k+1}}$

which is what we needed. QED

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3 years ago

The sales of homes in a new development have been increasing. In January, 5 homes were sold, in February,

Rama09 [41]

Answer: $a_n=7n-2$

Step-by-step explanation:

Let we consider sales of home in January as first term for sequence, then sales in February will be 2nd term and so on.

According to the given information, we have

First term : $a_1=5$

Second term : $a_2= 12=5+7$

Third term : $a_3= 19=12+7$

We can see that, Common difference = 7

Explicit rule for Arithmetic sequence :

$a_n=a_1+(n-1)d$

Put $a_1=5$ and d=7

$a_n=5+(n-1)7\\\\ a_n=5+7n-7\\\\ a_n=7n+5-7\\\\ a_n=7n-2$

The required explicit rule that can be used to find the number of homes sold in the nth month of the year : $a_n=7n-2$

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4 years ago

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