Answer:
-385
Step-by-step explanation:
If -5 = x, then f(x) = -15-365-5 which is -385.
Answer:
-10/16
Step-by-step explanation:
-7z3=-10 and 7-(-9)=16

Plug in 8 for y and 0 for x and solve.
hmmm what would it be the bisector point of a line with those points? let's check

now, let's check the slope of those two points, bearing in mind that a perpendicular line will have a <u>negative reciprocal slope</u> to that one.
![\bf (\stackrel{x_1}{4}~,~\stackrel{y_1}{1})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{-5}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-5-1}{2-4}\implies \cfrac{-6}{-2}\implies 3 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{3\implies \cfrac{3}{1}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{1}{3}}\qquad \stackrel{negative~reciprocal}{-\cfrac{1}{3}}}](https://tex.z-dn.net/?f=%5Cbf%20%28%5Cstackrel%7Bx_1%7D%7B4%7D~%2C~%5Cstackrel%7By_1%7D%7B1%7D%29%5Cqquad%20%28%5Cstackrel%7Bx_2%7D%7B2%7D~%2C~%5Cstackrel%7By_2%7D%7B-5%7D%29%20%5C%5C%5C%5C%5C%5C%20slope%20%3D%20m%5Cimplies%20%5Ccfrac%7B%5Cstackrel%7Brise%7D%7B%20y_2-%20y_1%7D%7D%7B%5Cstackrel%7Brun%7D%7B%20x_2-%20x_1%7D%7D%5Cimplies%20%5Ccfrac%7B-5-1%7D%7B2-4%7D%5Cimplies%20%5Ccfrac%7B-6%7D%7B-2%7D%5Cimplies%203%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Bperpendicular%20lines%20have%20%5Cunderline%7Bnegative%20reciprocal%7D%20slopes%7D%7D%20%7B%5Cstackrel%7Bslope%7D%7B3%5Cimplies%20%5Ccfrac%7B3%7D%7B1%7D%7D%5Cqquad%20%5Cqquad%20%5Cqquad%20%5Cstackrel%7Breciprocal%7D%7B%5Ccfrac%7B1%7D%7B3%7D%7D%5Cqquad%20%5Cstackrel%7Bnegative~reciprocal%7D%7B-%5Ccfrac%7B1%7D%7B3%7D%7D%7D)
so, we're really looking for the equation of a line whose slope is -1/3 and runs through (3, -2)
