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3 years ago

Find the horizontal asymptote of the graph of Y=(-3x^5+5x+4)/(6x^5+2x+5)

Mathematics

2 answers:

jek_recluse [69]3 years ago

8 0

Answer:

Horizontal asymptote

$y=-\dfrac{1}{2}$

Step-by-step explanation:

Given: $y=\dfrac{-3x^5+5x+4}{6x^5+2x+5}$

We need to find horizontal asymptote

For horizontal asymptote, we check the degree of numerator and denominator

Degree of numerator = 5

Degree of denominator = 5

Here degree is same

Therefore, Horizontal asymptote, y= leading coefficient of numerator over leading coefficient of denominator

Leading coefficient of numerator = -3

Leading coefficient of denominator = 6

Horizontal asymtote:

$y=\dfrac{-3}{6}=-\dfrac{1}{2}$

Hence, The horizontal asymptote is $y=-\dfrac{1}{2}$

Elden [556K]3 years ago

5 0

MrBillDoesMath!

Answer: y = -1/2

Discussion:

As x approaches plus or minus infinity the function behaves like

(-3x^5)/ (6x^5) = -1/2

MrB

You might be interested in

Sue used to have a square garage with 286 ft squared of floor space. He recently built an addition to it. The garage is still a

nekit [7.7K]

Answer:

New Length = 20.71 feet

Original Length = 16.91 feet

22.47%

Step-by-step explanation:

Original area of the square garage = 286 ft squared

Addition of 50% more space

New area of the garage = 286 + .50(286)

= 286 + 143

= 429 square feet

What was the length of one side of the garage originally?

Original area of the square garage = 286 ft squared

Area of a square = length^2

286 = length^2

Find the square root of both sides

√286 = √length^2

Original Length = 16.91 feet

What is the length of one side of the garage now?

New area of the garage = 429 square feet

Area of a square = length^2

429 = length^2

Find the square root of both sides

√429 = √length^2

New Length = 20.71 feet

What was the percent increase in the length of one side?

(New length - old length) / old length × 100

= (20.71 feet - 16.91 feet) / 16.91 feet × 100

= 3.8 feet / 16.91 feet × 100

= 0.2247 × 100

= 22.47%

3 0

3 years ago

If s(x)=2-x^2 and t(x)=3x, which value is equivalent to (s*t)(-7)?

andreyandreev [35.5K]

Answer:

(s*t)(-7) = 987

Step-by-step explanation:

s(x) = 2 - x²

t(x) = 3x

To find (s*t)(x), multiply s(x) and t(x).

(s*t)(x) = (2 - x²)(3x)

(s*t)(x) = 6x - 3x³

Now that you have (s*t)(x), plug -7 in.

(s*t)(-7) = 6(-7) - 3(-7)³

(s*t)(-7) = 6(-7) - 3(-343)

(s*t)(-7) = -42 + 1029

(s*t)(-7) = 987

5 0

4 years ago

Find the derivative of f(x) = 4x + 7 at x = 5.(2 points)

Sveta_85 [38]

Answer:

x=4x+7=

x=5=

Step-by-step explanation:

5 0

4 years ago

A system of equations is shown below: x + 3y = 5 (equation 1) 7x − 8y = 6 (equation 2) A student wants to prove that if equation

eduard

First Let we solve the Original system of equations:

equation (1): $x+3y=5$

equation (2): $7x-8y=6$

Multiplying equation (1) by 7, we get

$7x+21y=35 -->(3)$

$7x-8y=6 --> (2)$

Subtracting,

$29y=29$ implies $y=1$

Then $x=5-3(1)=2$

Thus the solution of the original equation is $x=2, y=1.$

Now Let we form the new equation:

Equation 2 is kept unchanged:

Equation (2): $7x-8y=6$

Equation 1 is replaced with the sum of equation 1 and a multiple of equation 2:

Equation (1): $8x-5y=11$

Now solve this two equations: $8x-5y=11, \\ 7x-8y=6$

Multiply (1) by 7 and (2) by 8,

$56x-35y=77$

$56x-64y=48$

Subtracting, $29y=29$ implies $y=1$

Then x=2.

so the solution for the new system of equation is x=2, y=1.

This Show that the solution to the system of equations 8x − 5y = 11 and 7x − 8y = 6 is the same as the solution to the given system of equations

4 0

3 years ago

Read 2 more answers

nalin [4]

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1200 x 0.85 = 1020

The sale price is $1020

Have A Nice Day ❤

Stay Brainly! ヅ

- Ally ✧

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6 0

3 years ago