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Misha Larkins [42]
3 years ago
7

I need help to start the problem.

Mathematics
1 answer:
Snezhnost [94]3 years ago
7 0
You would get x by itself first and go from there.
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The regular price of the soccer ball is $25. During the sale, it is 20 percent off. Use ratio reasoning to find x, the amount th
Evgen [1.6K]

$ 5 is taken is off the regular price

<em><u>Solution:</u></em>

Given that, Regular price of the soccer ball is $ 25

During the sale, it is 20 percent off

Let "x" be the amount that is taken off the regular price

Regular price = $ 25

Discount = 20 percent off

Which means, 20 % of regular price is taken off

x = 20 % of regular price

x = 20 % of 25

x = \frac{20}{100} \times 25\\\\x = 5

Thus $ 5 is taken is off the regular price

3 0
3 years ago
If 2(x + 3) + 7x = 3(x - 2) - 9, then x = ?
Fudgin [204]

Answer:

x=− 7 over 2 =−3.500

Hope this helps!

5 0
3 years ago
Read 2 more answers
pyramid t is a square pyramid with a base side length of 2 inches and a height of 6 inches what is the volume
fredd [130]

28.33 inches with an exponent of 2.

4 0
3 years ago
The area of the following parallelogram is:<br> 5 m<br> 4 m<br> 3 m
Sonbull [250]

Answer:

60m

Step-by-step explanation:

Multiply length times width times height so basically 5mx4mx3m=60m

Hope this helped :)

6 0
3 years ago
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Solve with cramer's rule x+2y+3z=11, 2x+y+2z=10, 3x+2y+z=9
nalin [4]

Answer:

x = 2 , y = 0 , z = 3

Step-by-step explanation:

Cramer's rule is a rule through which we can find the solution of linear equation.

we have the three linear equations as

x+2y+3z=11

2x+y+2z=10

3x+2y+z=9

AX=B  

A: coefficient matrix

X= unknown vectors(x,y,z)

D = values of the linear equation (11 , 10 , 9)

now we find the determinant of the given linear equation

determinant of the matrix will be

A = \left[\begin{array}{ccc}1&2&3\\2&1&2\\3&2&1\end{array}\right]  = 1(1-4) - 2(2-6) + 3(4 - 3)

                    = 1(-3) - 2(-4) + 3(1)

                    = -3+8+3 = 8

also D\neq 0

so the determinant is Non zero we can apply Cramer's rule

we will be replacing the first column of the coefficient matrix A with the values of D

by replacing the first column we will get the value of the variable 'x'

Dx =  \left[\begin{array}{ccc}11&2&3\\10&1&2\\9&2&1\end{array}\right]   = 11(1-4) -2(10-18) + 3(20-9) = -33+16+33 = 16

x = \frac{Dx}{D}  = \frac{16}{8} = 2

similarly

Dy = \left[\begin{array}{ccc}1&11&3\\2&10&2\\3&9&1\end{array}\right] = 1(10-18) -11(2-6) + 3(18 -30) = -8 +44 -36 = 0

y = \frac{Dy}{D} = 0

Dz= \left[\begin{array}{ccc}1&2&11\\2&1&10\\3&2&9\end{array}\right] = 1(9 - 20) -2(18 - 30) + 11(4 -3) = -11 +24 +11 = 24

z = \frac{Dz}{D} = \frac{24}{8} = 3

so we have the solution as

x = 2 , y = 0 , z = 3

Therefore the solution for the given linear equations is (2,0,3).

3 0
3 years ago
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